📜  用于合并排序的Python程序

📅  最后修改于: 2022-05-13 01:56:56.615000             🧑  作者: Mango

用于合并排序的Python程序

合并排序是一种分而治之的算法。它将输入数组分成两半,为两半调用自身,然后合并两个排序的半。 merge()函数用于合并两半。 merge(arr, l, m, r) 是关键过程,假设 arr[l..m] 和 arr[m+1..r] 已排序,并将两个已排序的子数组合并为一个。

Python3
# Python program for implementation of MergeSort
 
# Merges two subarrays of arr[].
# First subarray is arr[l..m]
# Second subarray is arr[m+1..r]
 
 
def merge(arr, l, m, r):
    n1 = m - l + 1
    n2 = r - m
 
    # create temp arrays
    L = [0] * (n1)
    R = [0] * (n2)
 
    # Copy data to temp arrays L[] and R[]
    for i in range(0, n1):
        L[i] = arr[l + i]
 
    for j in range(0, n2):
        R[j] = arr[m + 1 + j]
 
    # Merge the temp arrays back into arr[l..r]
    i = 0     # Initial index of first subarray
    j = 0     # Initial index of second subarray
    k = l     # Initial index of merged subarray
 
    while i < n1 and j < n2:
        if L[i] <= R[j]:
            arr[k] = L[i]
            i += 1
        else:
            arr[k] = R[j]
            j += 1
        k += 1
 
    # Copy the remaining elements of L[], if there
    # are any
    while i < n1:
        arr[k] = L[i]
        i += 1
        k += 1
 
    # Copy the remaining elements of R[], if there
    # are any
    while j < n2:
        arr[k] = R[j]
        j += 1
        k += 1
 
# l is for left index and r is right index of the
# sub-array of arr to be sorted
 
 
def mergeSort(arr, l, r):
    if l < r:
 
        # Same as (l+r)//2, but avoids overflow for
        # large l and h
        m = l+(r-l)//2
 
        # Sort first and second halves
        mergeSort(arr, l, m)
        mergeSort(arr, m+1, r)
        merge(arr, l, m, r)
 
 
# Driver code to test above
arr = [12, 11, 13, 5, 6, 7]
n = len(arr)
print("Given array is")
for i in range(n):
    print("%d" % arr[i],end=" ")
 
mergeSort(arr, 0, n-1)
print("\n\nSorted array is")
for i in range(n):
    print("%d" % arr[i],end=" ")
 
# This code is contributed by Mohit Kumra


输出
Given array is
12 11 13 5 6 7 

Sorted array is
5 6 7 11 12 13 

请参阅有关合并排序的完整文章以获取更多详细信息!