SymPy | Python中的 Polyhedron.vertices()

Polyhedron.vertices() : vertices()是一个 sympy Python库函数，它返回多面体的顶点。

Syntax : sympy.combinatorics.Polyhedrons.Polyhedron.vertices()

Return : vertices of the Polyhedron.

代码 #1：vertices() 示例——四面体

# Python code explaining
# SymPy.Polyhedron.vertices()
  
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.polyhedron import tetrahedron, octahedron
  
# Using from 
# sympy.combinatorics.polyhedron.Polyhedron.vertices()
  
# Creating Polyhedron
a = tetrahedron.copy()
  
print ("Polyhedron - vertices form : ", a.vertices)
  
a.rotate(0)
print ("\nPolyhedron - vertices form : ", a.vertices)

输出 ：

Polyhedron – vertices form : (0, 1, 2, 3)

Polyhedron – vertices form : (0, 2, 3, 1)

代码 #2 : vertices() 示例 – 八面体

# Python code explaining
# SymPy.Polyhedron.vertices()
  
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.polyhedron import tetrahedron, octahedron
  
# Using from 
# sympy.combinatorics.polyhedron.Polyhedron.vertices()
  
# Creating Polyhedron
a = octahedron.copy()
  
print ("Polyhedron - vertices form : ", a.vertices)
  
a.rotate(0)
print ("\nPolyhedron - vertices form : ", a.vertices)

输出 ：

Polyhedron – vertices form : (0, 1, 2, 3, 4, 5)

Polyhedron – vertices form : (0, 2, 3, 4, 1, 5)