SymPy | Python中的 Polyhedron.edges()

Polyhedron.edges() ：edges()是一个 sympy Python库函数，它返回多面体的边。

Syntax :
sympy.combinatorics.Polyhedrons.Polyhedron.edges()

Return :
edges of the Polyhedron.

代码#1：edges() 示例——四面体

# Python code explaining
# SymPy.Polyhedron.edges()
  
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.polyhedron import tetrahedron, octahedron
  
# Using from 
# sympy.combinatorics.polyhedron.Polyhedron.edges()
  
# Creating Polyhedron
a = tetrahedron.copy()
  
print ("Polyhedron - edges form : ", a.edges)
  
a.rotate(0)
print ("\nPolyhedron - edges form : ", a.edges)

输出 ：

Polyhedron – edges form : {(0, 1), (0, 2), (0, 3), (1, 2), (1, 3), (2, 3)}

Polyhedron – edges form : {(0, 1), (0, 2), (0, 3), (1, 2), (1, 3), (2, 3)}

代码#2：edges() 示例——八面体

# Python code explaining
# SymPy.Polyhedron.edges()
  
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.polyhedron import tetrahedron, octahedron
  
# Using from 
# sympy.combinatorics.polyhedron.Polyhedron.edges()
  
# Creating Polyhedron
a = octahedron.copy()
  
print ("Polyhedron - edges form : ", a.edges)
  
a.rotate(0)
print ("\nPolyhedron - edges form : ", a.edges)

输出 ：

Polyhedron – edges form : {(0, 1), (0, 2), (0, 3), …, (3, 4), (3, 5), (4, 5)}

Polyhedron – edges form : {(0, 1), (0, 2), (0, 3), …, (3, 4), (3, 5), (4, 5)}