SymPy | Python中的 Polyhedron.cyclic_form()

Polyhedron.cyclic_form() : cyclic_form()是一个 sympy Python库函数，它以循环表示法返回角的索引。

Syntax :
sympy.combinatorics.Polyhedrons.Polyhedron.cyclic_form()

Return :
indices of the corners in cyclic notation

代码 #1 : cyclic_form() 示例——四面体

# Python code explaining
# SymPy.Polyhedron.cyclic_form()
  
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.polyhedron import tetrahedron, octahedron
  
# Using from 
# sympy.combinatorics.polyhedron.Polyhedron.cyclic_form()
  
# Creating Polyhedron
a = tetrahedron.copy()
  
print ("Polyhedron - cyclic_form form : ", a.cyclic_form)
  
a.rotate(0)
print ("\nPolyhedron - cyclic_form form : ", a.cyclic_form)

输出 ：

Polyhedron – cyclic_form form : []

Polyhedron – cyclic_form form : [[1, 2, 3]]

代码 #2 : cyclic_form() 示例 – 八面体

# Python code explaining
# SymPy.Polyhedron.cyclic_form()
  
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.polyhedron import tetrahedron, octahedron
  
# Using from 
# sympy.combinatorics.polyhedron.Polyhedron.cyclic_form()
  
# Creating Polyhedron
a = octahedron.copy()
  
print ("Polyhedron - cyclic_form form : ", a.cyclic_form)
  
a.rotate(0)
print ("\nPolyhedron - cyclic_form form : ", a.cyclic_form)

输出 ：

Polyhedron – cyclic_form form : []

Polyhedron – cyclic_form form : [[1, 2, 3, 4]]