算术级数系列第N项程序

给定第一个项(a)，共同差(d)和算术级数级数的整数N，任务是找到级数的N^个项。
例子 ：

Input : a = 2 d = 1 N = 5
Output :
The 5th term of the series is : 6

Input : a = 5 d = 2 N = 10
Output :
The 10th term of the series is : 23

方法：

We know the Arithmetic Progression series is like = 2, 5, 8, 11, 14 …. … 
In this series 2 is the stating term of the series . 
Common difference = 5 – 2 = 3 (Difference common in the series). 
so we can write the series as :
t₁ = a₁ 
t₂ = a₁ + (2-1) * d 
t₃ = a₁ + (3-1) * d 
. 
. 
. 
t_N = a₁ + (N-1) * d 
 

为了找到算术级数系列中的第N^个项，我们使用简单的公式。

TN = a1 + (N-1) * d

C++

// CPP Program to find nth term of
// Arithmetic progression
#include 
using namespace std;
 
int Nth_of_AP(int a, int d, int N)
{
    // using formula to find the
    // Nth term t(n) = a(1) + (n-1)*d
    return (a + (N - 1) * d);
     
}
 
// Driver code
int main()
{
    // starting number
    int a = 2;
     
    // Common difference
    int d = 1;
     
    // N th term to be find
    int N = 5;
     
    // Display the output
    cout << "The "<< N
         <<"th term of the series is : "
         << Nth_of_AP(a,d,N);
 
    return 0;
}

Java

// Java program to find nth term
// of Arithmetic progression
import java.io.*;
import java.lang.*;
 
class GFG
{
    public static int Nth_of_AP(int a,
                                int d,
                                int N)
    {
        // using formula to find the Nth
        // term t(n) = a(1) + (n-1)*d
        return ( a + (N - 1) * d );
    }
 
    // Driver code
    public static void main(String[] args)
    {
        // starting number
        int a = 2;
         
        // Common difference
        int d = 1;
         
        // N th term to be find
        int N = 5;
 
        // Display the output
        System.out.print("The "+ N +
                         "th term of the series is : " +
                          Nth_of_AP(a, d, N));
    }
}

Python3

# Python 3 Program to
# find nth term of
# Arithmetic progression
 
def Nth_of_AP(a, d, N) :
 
    # using formula to find the
    # Nth term t(n) = a(1) + (n-1)*d
    return (a + (N - 1) * d)
      
  
# Driver code
a = 2  # starting number
d = 1  # Common difference
N = 5  # N th term to be find
  
# Display the output
print( "The ", N ,"th term of the series is : ",
       Nth_of_AP(a, d, N))
 
 
 
# This code is contributed
# by Nikita Tiwari.

C#

// C# program to find nth term
// of Arithmetic progression
using System;
 
class GFG
{
    public static int Nth_of_AP(int a,
                                int d,
                                int N)
    {
         
        // using formula to find the Nth
        // term t(n) = a(1) + (n-1)*d
        return ( a + (N - 1) * d );
    }
 
    // Driver code
    public static void Main()
    {
        // starting number
        int a = 2;
         
        // Common difference
        int d = 1;
         
        // N th term to be find
        int N = 5;
 
        // Display the output
        Console.WriteLine("The "+ N +
                          "th term of the series is : " +
                           Nth_of_AP(a, d, N));
    }
}
 
// This code is contributed by vt_m.

Javascript

 
// JavaScript Program to find nth term of 
// Arithmetic progression
 
    function Nth_of_AP(a, d, N)
    { 
        // using formula to find the 
        // Nth term t(n) = a(1) + (n-1)*d
        return (a + (N - 1) * d);
       
    }
   
    // Driver code
 
    // starting number
    let a = 2; 
       
    // Common difference
    let d = 1; 
       
    // N th term to be find
    let N = 5; 
       
    // Display the output
    document.write("The "+ N + "th term of the series is : "
    + Nth_of_AP(a,d,N));
   
 
// This code is contributed by Mayank Tyagi
 

输出 ：

The 5th term of the series is : 6