求出1,8,27,64…的n个项的总和。

给定一个序列，任务是找到以下序列之和，最多n个项：

1, 8, 27, 64, …

例子：

Input: N = 2
Output: 9
9 = (2*(2+1)/2)^2

Input: N = 4
Output: 100
100 = (4*(4+1)/2)^2

方法：我们可以使用以下公式解决此问题：

Sn = 1 + 8 + 27 + 64 + .........up to n terms
    Sn = (n*(n+1)/2)^2

下面是上述opf的实现方法：

C++

// C++ program to find the sum of n terms
#include 
using namespace std;
 
// Function to calculate the sum
int calculateSum(int n)
{
 
    // Return total sum
    return pow(n * (n + 1) / 2, 2);
}
 
// Driver code
int main()
{
 
    int n = 4;
    cout << calculateSum(n);
 
    return 0;
}

Java

// Java program to find the sum of n terms
import java.io.*;
 
class GFG {
 
 
// Function to calculate the sum
static int calculateSum(int n)
{
 
    // Return total sum
    return (int)Math.pow(n * (n + 1) / 2, 2);
}
 
// Driver code
 
 
    public static void main (String[] args) {
        int n = 4;
    System.out.println( calculateSum(n));
 
    }
}
// This code is contributed by inder_verma..

Python3

# Python3 program to find the
# sum of n terms
 
#Function to calculate the sum
def calculateSum(n):
     
    #return total sum
    return (n * (n + 1) / 2)**2
     
#Driver code
if __name__=='__main__':
    n = 4
    print(calculateSum(n))
 
#this code is contributed by Shashank_Sharma

C#

// C# program to find the sum of n terms
using System;
 
class GFG
{
 
// Function ot calculate the sum
static int calculateSum(int n)
{
 
    // Return total sum
    return (int)Math.Pow(n * (n + 1) / 2, 2);
}
 
// Driver code
public static void Main ()
{
    int n = 4;
    Console.WriteLine(calculateSum(n));
}
}
 
// This code is contributed
// by Akanksha Rai(Abby_akku)

Javascript

 
// javascript program to find the sum of n terms
 
// Function to calculate the sum
function calculateSum(n)
{
 
    // Return total sum
    return parseInt(Math.pow(n * (n + 1) / 2, 2));
}
 
// Driver code
 var n = 4;
document.write( calculateSum(n));
 
 
// This code contributed by shikhasingrajput
 

输出：

100