找出 3 到 4 之间的无理数
不能表示为简单分数的实数称为无理数。它不能像 p/q 这样的比率来表示，其中 p 和 q 都是整数，q≠0。无理数是任何不是有理数的数。无理数可以用小数表示，但不能用分数表示，这意味着它们不能表示为两个整数的比率。在小数点之后，无理数有无限数量的非重复数字。
无理数的十进制展开既不结束也不重复。无理数的定义是一个没有比率或无法说明比率的数，即除了使用根之外不能以任何其他方式表示的数。换句话说，无理数不能表示为两个整数的比率。
无理数的例子
√2、√3、√5 等是无理数的一些例子，因为它们不能以 p ⁄ q 的形式表示。欧拉数、黄金比例、π等也是无理数的一些例子。 1/0、2/0、3/0 等等都是非理性的，因为它们给了我们无限的价值。
找出 3 到 4 之间的无理数
解决方案：
Irrational numbers are real numbers that cannot be written in the form p/q, where p and q are integers and q≠0. For instance, √2 and √3 and so on are irrational. A rational number is any number that can be written in the form of p/q, where p and q are both integers and q≠0.
Here, the given numbers are 3 and 4. There can be an infinite number of irrational numbers between these numbers. The numbers between the squares of 3 and 4, i.e., between 9 and 16 are 10, 11, …14, 15. The square root of any of these numbers is always an irrational number. The square root of 10, i.e., √10 is an irrational number that lies between 3 and 4.
类似问题
问题1：4和5之间的无理数是多少？
解决方案：
Here, the given numbers are 4 and 5. The numbers between the squares of 4 and 5, i.e., between 16 and 25 are 17, 18, …23, 24. The square root of any of these numbers is always an irrational number. The square root of 19, i.e., √19 is an irrational number that lies between 4 and 5.
问题2：5和6之间的无理数是多少？
解决方案：
Here, the given numbers are 5 and 6. The numbers between the squares of 5 and 6, i.e., between 25 and 36 are 26, 27, …34, 35. The square root of any of these numbers is always an irrational number. The square root of 27, i.e., √27 is an irrational number that lies between 5 and 6.
问题3：1和2之间的无理数是多少？
解决方案：
Here, the given numbers are 1 and 2. The numbers between the squares of 1 and 2, i.e., between 1 and 4 are 2 and 3. The square root of any of these numbers is always an irrational number. The square root of 3, i.e., √3 is an irrational number that lies between 1 and 2.
问题 4：-1 和 3 之间的无理数是多少？
解决方案：
Here, the given numbers are -1 and 3. The square root of 2, i.e., √2 is an irrational number that lies between -1 and 3.