距离旅行公式
行进距离描述了物体在特定时间跨度内所经过的路径。它是物体从一个点到另一个点所走路径的度量。物体行进的距离可以通过该物体的速度与该物体在行进过程中所用时间的乘积来获得。在速度的情况下，行进的距离是速度和时间的乘积。距离米 (m) 的 SI 单位。行驶距离公式如下：
d = v*t
where,
d = distance traveled by the object,
v = velocity of the object,
t = time taken by the object to travel the distance
在某些情况下，当给定物体的速度时，公式中的速度会被速度代替。
示例问题
问题 1：一个物体以 5 m/s 的速度在 5 s 内运动，求该物体运动的距离。
回答：
Given: v = 5 m/s, t = 5 s
d = v*t
= 5*5
d = 25 m
Thus, the distance travelled by the object in 5 s with a velocity of 5 m/s is 25 m.
问题 2：如果速度为 500 cm/s，所用时间为 10 s，请确定汽车行驶的距离。
回答：
Given: v = 500 cm/s, t = 10 s
d = v*t
= 500*10
d = 5000 cm = 50 m
Thus, the distance traveled by the object is 50 m.
问题 3：计算一辆车在 60 秒内以 30 m/s 的恒定速度行驶的距离。
回答：
First calculate the distance traveled using the formula above, where v = 30m/s and t = 60s.
d = v*t
d = 30m/s*60s
d = 1800m.
问题 4：计算一个物体在 20 秒内匀速行进 100 米的速度。
答案：
To calculate the velocity, we will use the above equation clearing v, where d = 100m and t = 20s.
d = v*t
v = d/t
v = 100m/20s
v = 5m/s.
问题 5：一辆满载的卡车以每小时 50 公里的速度行驶。计算卡车行驶 200 公里所需的总时间？
解决方案：
Given parameters are:
Rate of the journey, r = 50 km/hr
Displacement, d = 200 km
Displacement d = r×t
Thus, the time taken will be given as:
t = d/r
= 200/50
= 4 hrs
Therefore time taken is 4 hours.
问题 6：如果一名运动员在 10 秒内跑完 250 米，而另一名运动员在 7 秒内跑完 210 米，则确定获胜者。
解决方案：
First athlete displacement = 250 m, and time taken = 10 s
Thus his rate of speed will be as per formula,
r1= 250/10
r1 = 25 m/s.
Displacement by the second athlete = 210 m and time taken = 7 s
Thus his rate of speed will be as per formula,
r2 = 210/7
r2 = 30 m/s.
Therefore, the 2nd athlete wins the race.