将给定N加1后更改的位数计数

给定一个整数$N$ 。任务是查找在给定数字加1后更改的位数。

例子：

Input : N = 5
Output : 2
After adding 1 to 5 it becomes 6.
Binary representation of 5 is 101.
Binary representation of 6 is 110.
So, no. of bits changed is 2.

Input : N = 1
Output : 2

有三种方法可以找到将给定值N加1后获得的结果中的更改位数：

• 方法1：将1与给定的整数相加，比较N的位数和相加后得到的结果，并对不匹配位数进行计数。
• 方法2：如果将1加到N，则更改的总位数由从右起第1个零的位置(即LSB为零)定义。在这种情况下，将1加1，然后对其进行更改，并将进位1传递到其下一位；但是，如果将1加到0，则只有0变为1，并且不再传递进位。
• 方法3：要查找将给定数字加1时已更改的位数，请对n和n + 1进行XOR，然后计算所得XOR值中的置位位数。

以下是方法3的实现：

C++

// CPP program to find the number
// of changed bit
#include 
using namespace std;
  
// Function to find number of changed bit
int findChangedBit(int n)
{
    // Calculate xor of n and n+1
    int XOR = n ^ (n + 1);
  
    // Count set bits in xor value
    int result = __builtin_popcount(XOR);
  
    // Return the result
    return result;
}
  
// Driver function
int main()
{
    int n = 6;
    cout << findChangedBit(n) << endl;
  
    n = 7;
    cout << findChangedBit(n);
  
    return 0;
}

Java

// Java program to find the number
// of changed bit
class GFG 
{
  
// Function to find number of changed bit
static int findChangedBit(int n)
{
    // Calculate xor of n and n+1
    int XOR = n ^ (n + 1);
  
    // Count set bits in xor value
    int result = Integer.bitCount(XOR);
  
    // Return the result
    return result;
}
  
// Driver code
public static void main(String[] args) 
{
    int n = 6;
    System.out.println(findChangedBit(n));
  
    n = 7;
    System.out.println(findChangedBit(n));
}
}
  
// This code contributed by Rajput-Ji

Python3

# Python 3 program to find the number
# of changed bit
  
# Function to find number of changed bit
def findChangedBit(n):
      
    # Calculate xor of n and n+1
    XOR = n ^ (n + 1)
  
    # Count set bits in xor value
    result = bin(XOR).count("1")
  
    # Return the result
    return result
  
# Driver Code
if __name__ == '__main__':
    n = 6
    print(findChangedBit(n))
  
    n = 7
    print(findChangedBit(n))
  
# This code is contributed by
# Surendra_Gangwar

C#

// C# program to find the number
// of changed bit
using System;
      
class GFG 
{
  
// Function to find number of changed bit
static int findChangedBit(int n)
{
    // Calculate xor of n and n+1
    int XOR = n ^ (n + 1);
  
    // Count set bits in xor value
    int result = bitCount(XOR);
  
    // Return the result
    return result;
}
static int bitCount(int x)
{
  
    // To store the count
    // of set bits
    int setBits = 0;
    while (x != 0) 
    {
        x = x & (x - 1);
        setBits++;
    }
  
    return setBits;
}
  
// Driver code
public static void Main(String[] args) 
{
    int n = 6;
    Console.WriteLine(findChangedBit(n));
  
    n = 7;
    Console.WriteLine(findChangedBit(n));
}
}
  
/* This code contributed by PrinciRaj1992 */

输出：

1
4