Python - 字典的对称差分

给定两个字典，任务是编写一个Python程序来获取对称差异。

例子：

Input : test_dict1 = {‘Gfg’ : 4, ‘is’ : 3, ‘best’ : 7, ‘for’ : 3, ‘geek’ : 4}, 

test_dict2 = {‘Gfg’ : 4, ‘is’ : 3, ‘good’ : 7, ‘for’ : 3, ‘all’ : 4}

Output : {‘all’: 4, ‘good’: 7, ‘best’: 7, ‘geek’: 4}

Explanation : all, good, best and geek are mutually unique keys.

Input : test_dict1 = {‘Gfg’ : 4, ‘is’ : 3, ‘good’ : 7, ‘for’ : 3, ‘geek’ : 4}, 

test_dict2 = {‘Gfg’ : 4, ‘is’ : 3, ‘good’ : 7, ‘for’ : 3, ‘all’ : 4}

Output : {‘all’: 4, ‘geek’: 4}

Explanation : all, geek are mutually unique keys.

方法 #1：使用 ^运算符+ keys() +字典理解

在此，我们使用 keys() 提取所有密钥，并使用 ^ 运算符获得所有密钥的对称差异。所需的字典是使用字典理解编译的。

Python3

# Python3 code to demonstrate working of
# Symmetric Difference of Dictionaries
# Using ^ operator + keys() + dictionary comprehension
  
# initializing dictionaries
test_dict1 = {'Gfg': 4, 'is': 3, 'best': 7, 'for': 3, 'geek': 4}
test_dict2 = {'Gfg': 4, 'is': 3, 'good': 7, 'for': 3, 'all': 4}
  
# printing original dictionaries
print("The original dictionary 1 is : " + str(test_dict1))
print("The original dictionary 2 is : " + str(test_dict2))
  
# getting symmetric difference using ^ operation
res = {key: test_dict1[key] if key in test_dict1 else test_dict2[key]
       for key in test_dict1.keys() ^ test_dict2.keys()}
  
# printing result
print("The symmetric difference : " + str(res))

输出：

The original dictionary 1 is : {‘Gfg’: 4, ‘is’: 3, ‘best’: 7, ‘for’: 3, ‘geek’: 4}

The original dictionary 2 is : {‘Gfg’: 4, ‘is’: 3, ‘good’: 7, ‘for’: 3, ‘all’: 4}

The symmetric difference : {‘geek’: 4, ‘best’: 7, ‘all’: 4, ‘good’: 7}

方法 #2：使用 set.symmetric_difference() + keys()

在这里，我们使用内置函数symmetric_difference() 执行获取不常见元素的任务。

蟒蛇3

# Python3 code to demonstrate working of
# Symmetric Difference of Dictionaries
# Using set.symmetric_difference() + keys()
  
# initializing dictionaries
test_dict1 = {'Gfg': 4, 'is': 3, 'best': 7, 'for': 3, 'geek': 4}
test_dict2 = {'Gfg': 4, 'is': 3, 'good': 7, 'for': 3, 'all': 4}
  
# printing original dictionaries
print("The original dictionary 1 is : " + str(test_dict1))
print("The original dictionary 2 is : " + str(test_dict2))
  
# computing sym. difference using set inbuilt function
res = {key: test_dict1[key] if key in test_dict1 else test_dict2[key] for key in
       set(test_dict1.keys()).symmetric_difference(test_dict2.keys())}
  
# printing result
print("The symmetric difference : " + str(res))

输出：

The original dictionary 1 is : {‘Gfg’: 4, ‘is’: 3, ‘best’: 7, ‘for’: 3, ‘geek’: 4}

The original dictionary 2 is : {‘Gfg’: 4, ‘is’: 3, ‘good’: 7, ‘for’: 3, ‘all’: 4}

The symmetric difference : {‘good’: 7, ‘all’: 4, ‘geek’: 4, ‘best’: 7}