给定一个包含N 个节点的循环单向链表，任务是从列表中找到其数据值具有偶数和的所有节点的和和乘积。
例子：
Input: List = 15 -> 16 -> 8 -> 6 -> 13
Output: Sum = 42, Product = 9360
Explanation:
The circular linked list contains:
15 -> 1 + 5 = 6
16 -> 1 + 6 = 7
8 -> 8
6 -> 6
13 -> 1 + 3 = 4
The list contains 4 Even Digit Sum data values 15, 8, 6 and 13.
Sum = 15 + 8 + 6 + 13 = 42
Product = 15 * 8 * 6 * 13 = 9360
Input: List = 5 -> 3 -> 4 -> 2 -> 9
Output: Sum = 6, Product = 8
Explanation:
The list contains 2 Even Digit Sum data values 4 and 2.
Sum = 4 + 2 = 6
Product = 4 * 2 = 8
方法：
- 用循环链表的头部初始化一个指针 current，用 0 初始化一个 sum 变量sum ，用 1 初始化一个 product 变量product 。
- 开始使用 do-while 循环遍历链表，直到遍历所有节点。
- 如果当前节点数据值具有偶数和。
- 将当前节点的值添加到总和中，即sum = sum + current -> data 。
- 将当前节点的值乘以产品即product = product * current -> data 。
- 增加指向链表下一个节点的指针，即temp = temp -> next 。
- 打印总和和乘积。
下面是上述方法的实现：
C++
// C++ implementation to find the sum and
// product of all of the Even Digit sum nodes
// in a circularly linked list
#include
using namespace std;
// Circular list node
struct Node {
int data;
struct Node* next;
};
// Function to find the digit sum
// for a number
int digitSum(int num)
{
int sum = 0;
while (num) {
sum += (num % 10);
num /= 10;
}
return sum;
}
// Function to calculate sum and
// product
void SumProduct(struct Node* head,
int key)
{
struct Node* current = head;
int sum = 0, product = 1;
// If list is empty simply
// show message
if (head == NULL) {
printf("\nList is empty\n");
return;
}
// Traverse first to last node
else {
do {
// Check if current node's
// data has an even digit sum
if (!(digitSum(current->data)
& 1))
{
// Calculate sum
sum += current->data;
// Calculate product
product *= current->data;
}
current = current->next;
} while (current != head);
}
cout << "Sum = " << sum
<< ", Product = " << product;
}
// Function print the list
void DisplayList(struct Node* head)
{
struct Node* current = head;
// If list is empty simply
// show message
if (head == NULL)
{
printf("\nList is empty\n");
return;
}
// Traverse first to last node
else {
do {
printf("%d ", current->data);
current = current->next;
} while (current != head);
}
}
// Function to insert a node at the
// end of a Circular linked list
void InsertNode(struct Node** head,
int data)
{
struct Node* current = *head;
// Create a new node
struct Node* newNode = new Node;
// Check node is created or not
if (!newNode) {
printf("\nMemory Error\n");
return;
}
// Insert data into newly
// created node
newNode->data = data;
// Check list is empty
// if not have any node then
// make first node it
if (*head == NULL) {
newNode->next = newNode;
*head = newNode;
return;
}
// If list have already some node
else {
// Move first node to last
// node
while (current->next != *head)
{
current = current->next;
}
// Put first or head node
// address in new node link
newNode->next = *head;
// Put new node address into
// last node link(next)
current->next = newNode;
}
}
// Driver Code
int main()
{
struct Node* head = NULL;
InsertNode(&head, 13);
InsertNode(&head, 6);
InsertNode(&head, 8);
InsertNode(&head, 15);
InsertNode(&head, 16);
cout << "Initial List: ";
DisplayList(head);
cout << endl;
SumProduct(head, 11);
return 0;
} Java
// Java implementation to find the sum and
// product of all of the Even Digit sum nodes
// in a circularly linked list
class GFG{
// Structure for a node
static class Node{
int data;
Node next;
}
// Function to calulate the sum of
// indivdual digits
static int digitSum(int n)
{
int sum = 0;
while (n != 0)
{
sum += n % 10;
n /= 10;
}
return sum;
}
// Function to calculate sum and
// product
static void SumProduct(Node head)
{
Node temp = head;
int Sum = 0;
int Prod = 1;
do
{
// Check if current node's
// data has an even digit sum
if (digitSum(temp.data) % 2 == 0)
{
Sum += temp.data;
Prod *= temp.data;
}
temp = temp.next;
} while (temp != head);
System.out.print("Sum = " + Sum);
System.out.print(", Product = " + Prod);
}
// Function print the list
static void DisplayList(Node head)
{
Node temp = head;
if (head != null)
{
do
{
// Traverse first to last node
System.out.print(temp.data + " ");
temp = temp.next;
} while (temp != head);
}
System.out.println();
}
// Function to insert a node at the ending
// of a Circular linked list
static Node InsertNode(int key, Node head)
{
// Create a new node
Node new_node = new Node();
new_node.data = key;
// If linked list is null then
// make the first node as head
// after insertion
if (head == null)
{
head = new_node;
new_node.next = head;
}
else
{
// traverse to the end and insert
// node at the end and make
// it point to the head
Node temp = head;
while (temp.next != head)
{
temp = temp.next;
}
temp.next = new_node;
new_node.next = head;
}
return head;
}
// Driver code
public static void main(String args[])
{
Node head = null;
head = InsertNode(13, head);
head = InsertNode(6, head);
head = InsertNode(8, head);
head = InsertNode(15, head);
head = InsertNode(16, head);
System.out.print("Initial List: ");
DisplayList(head);
SumProduct(head);
}
}
// This code is contributed by nishkarsh146Python3
# Python3 implementation to find the
# sum and product of all of the Even
# Digit sum nodes in a circularly
# linked list
# Circular list node
class Node:
def __init__(self, x):
self.data = x
self.next = None
# Function to find the digit sum
# for a number
def digitSum(num):
sum = 0
while (num):
sum += (num % 10)
num //= 10
return sum
# Function to calculate sum and
# product
def SumProduct(head, key):
current = head
sum = 0
product = 1
# If list is empty simply
# show message
if (head == None):
print("List is empty")
return
# Traverse first to last node
else:
while (True):
# Check if current node's
# data has an even digit sum
if (not (digitSum(current.data) & 1)):
# Calculate sum
sum += current.data
# Calculate product
product *= current.data
current = current.next
if current == head:
break
print("Sum =", sum,
", Product = ", product)
# Function print the list
def DisplayList(head):
current = head
# If list is empty simply
# show message
if (head == None):
print("List is empty\n")
return
# Traverse first to last node
else:
while True:
print(current.data, end = " ")
current = current.next
if current == head:
break
# Function to insert a node at the
# end of a Circular linked list
def InsertNode(head, data):
current = head
# Create a new node
newNode = Node(data)
# Check node is created or not
if (not newNode):
print("Memory Error")
return
# Check list is empty
# if not have any node then
# make first node it
if (head == None):
newNode.next = newNode
head = newNode
return head
# If list have already some node
else:
# Move first node to last
# node
while (current.next != head):
current = current.next
# Put first or head node
# address in new node link
newNode.next = head
# Put new node address into
# last node link(next)
current.next = newNode
return head
# Driver Code
if __name__ == '__main__':
head = None
head = InsertNode(head, 13)
head = InsertNode(head, 6)
head = InsertNode(head, 8)
head = InsertNode(head, 15)
head = InsertNode(head, 16)
print("Initial List: ", end = " ")
DisplayList(head)
print()
SumProduct(head, 11)
# This code is contributed by mohit kumar 29C#
// C# implementation to find the sum and
// product of all of the Even Digit sum nodes
// in a circularly linked list
using System;
class GFG{
// Structure for a node
class Node
{
public int data;
public Node next;
}
// Function to calulate the sum of
// indivdual digits
static int digitSum(int n)
{
int sum = 0;
while (n != 0)
{
sum += n % 10;
n /= 10;
}
return sum;
}
// Function to calculate sum and
// product
static void SumProduct(Node head)
{
Node temp = head;
int Sum = 0;
int Prod = 1;
do
{
// Check if current node's
// data has an even digit sum
if (digitSum(temp.data) % 2 == 0)
{
Sum += temp.data;
Prod *= temp.data;
}
temp = temp.next;
} while (temp != head);
Console.Write("Sum = " + Sum);
Console.Write(", Product = " + Prod);
}
// Function print the list
static void DisplayList(Node head)
{
Node temp = head;
if (head != null)
{
do
{
// Traverse first to last node
Console.Write(temp.data + " ");
temp = temp.next;
} while (temp != head);
}
Console.WriteLine();
}
// Function to insert a node at the ending
// of a Circular linked list
static Node InsertNode(int key, Node head)
{
// Create a new node
Node new_node = new Node();
new_node.data = key;
// If linked list is null then
// make the first node as head
// after insertion
if (head == null)
{
head = new_node;
new_node.next = head;
}
else
{
// traverse to the end and insert
// node at the end and make
// it point to the head
Node temp = head;
while (temp.next != head)
{
temp = temp.next;
}
temp.next = new_node;
new_node.next = head;
}
return head;
}
// Driver code
public static void Main(String []args)
{
Node head = null;
head = InsertNode(13, head);
head = InsertNode(6, head);
head = InsertNode(8, head);
head = InsertNode(15, head);
head = InsertNode(16, head);
Console.Write("Initial List: ");
DisplayList(head);
SumProduct(head);
}
}
// This code is contributed by 29AjayKumar输出：
Initial List: 13 6 8 15 16
Sum = 42, Product = 9360如果您想与行业专家一起参加直播课程，请参阅Geeks Classes Live