检查字符串包含长度均匀的回文子字符串

S是仅包含小写英文字母的字符串。我们需要查找是否存在至少一个长度为偶数的回文子字符串。

例子：

Input  : aassss
Output : YES

Input  : gfg
Output : NO

请注意，即使长度的回文必须包含在中间的两个相同的字母。因此，我们只需要检查这种情况。如果在字符串找到两个连续的相同字母，则输出“是”，否则输出“否”。

下面是实现：

C++

// C++ program to check if there is a substring
// palindrome of even length.
#include 
using namespace std;
 
// function to check if two consecutive same
// characters are present
bool check(string s)
{
    for (int i = 0; i < s.length() - 1; i++)
        if (s[i] == s[i + 1])
            return true;
    return false;
}
 
int main()
{
    string s = "xzyyz";
    if (check(s))
        cout << "YES" << endl;
    else
        cout << "NO" << endl;
    return 0;
}

Java

// Java program to check if there is a substring
// palindrome of even length.
 
class GFG {
 
 
// function to check if two consecutive same
// characters are present
static boolean check(String s)
{
    for (int i = 0; i < s.length() - 1; i++)
        if (s.charAt(i) == s.charAt(i+1))
            return true;
    return false;
}
 
// Driver Code
    public static void main(String[] args) {
 
        String s = "xzyyz";
    if (check(s))
              System.out.println("YES");
    else
        System.out.println("NO");
    }
}

Python3

# Python 3 program to check if there is
# a substring palindrome of even length.
 
# function to check if two consecutive
# same characters are present
def check(s):
 
    for i in range (0, len(s)):
        if (s[i] == s[i + 1]):
            return True
             
    return False
 
# Driver Code
s = "xzyyz"
if(check(s)):
    print("YES")
else:
    print("NO")
     
# This code is contributed
# by iAyushRAJ

C#

// C# program to check if there is a substring
// palindrome of even length.
using System;
public class GFG {
 
 
// function to check if two consecutive same
// characters are present
static bool check(String s)
{
    for (int i = 0; i < s.Length - 1; i++)
        if (s[i] == s[i+1])
            return true;
    return false;
}
 
// Driver Code
    public static void Main() {
 
        String s = "xzyyz";
    if (check(s))
              Console.WriteLine("YES");
    else
        Console.WriteLine("NO");
    }
}

Javascript

 
// Javascript program to check if there is
// a substring palindrome of even length.
 
// Function to check if two consecutive same
// characters are present
function check(s)
{
    for(let i = 0; i < s.length - 1; i++)
        if (s[i] == s[i + 1])
            return true;
             
    return false;
}
 
// Driver code
let s = "xzyyz";
if (check(s))
      document.write("YES");
else
    document.write("NO");
     
// This code is contributed by suresh07
 

输出：

YES

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