构造一个长度为L的字符串，以使每个长度为X的子字符串都具有正好Y个不同的字母

给定字符串l的长度，子字符串x的长度以及长度为x的子字符串必须具有的不同字符数为y，任务是找到一个长度为l的字符串，其中每个长度x的子字符串都具有y字符鲜明。
例子：

Input: l = 6, x = 5, y = 3 
Output: abcabc 
Explanation: 
If we take a substring of the first five characters then the substring will be “abcab”. 
There are exactly three distinct characters (a, b, c) in the substring. 
Similarly, if we take any substring from the string of length 5 then it will have 
exactly 3 distinct characters.
Input: l = 3, x = 1, y = 1 
Output: aaa 
Explanation: 
If we take the substring of length 1 then it will have exactly 1 distinct character in it. 
 

方法：
为了解决上述问题，我们遵循以下步骤：

• 将变量p初始化为97，该变量标记小写字母“ a”的ASCII值。
• 不断增加p的值，直到y个字符。
• 然后从第一个字符重复该字符，直到其长度等于给定字符串的长度，然后返回最后一个字符串。

下面是上述方法的实现：

C++

// C++ implementation to
// construct a string of length L
// such that each substring of length
// X has exactly Y distinct letters.
#include 
using namespace std;
 
void String(int l, int x, int y)
{
    // Initialize p equal to the ASCII value of a
    int p = 97;
     
    // Iterate till the length of the string
    for(int j = 0; j < l ; j++)
    {
        char ans = (char)(p + (j % y));
        cout << ans;
    }
}
     
// Driver code
int main ()
{
    int l = 6;
    int x = 5;
    int y = 3;
    String(l, x, y) ;
    return 0;
}
 
// This code is contributed by AnkitRai01

Java

// Java implementation to
// construct a string of length L
// such that each substring of length
// X has exactly Y distinct letters.
 
public class GFG {
         
    static void string(int l, int x, int y){
         
        // Initialize p equal to the ASCII value of a
        int p = 97;
     
        // Iterate till the length of the string
        for(int j = 0; j < l ; j++){
             
            char ans = (char)(p + (j % y));
            System.out.print(ans);
        }
             
    }
     
    // Driver code
    public static void main (String[] args) {
    int l = 6;
    int x = 5;
    int y = 3;
    string(l, x, y) ;
        }
}
// This code is contributed by AnkitRai01

Python3

# Python implementation to
# construct a string of length L
# such that each substring of length
# X has exactly Y distinct letters.
 
def String(l, x, y):
    # Initialize p equal to the ASCII value of a
    p = 97
 
    # Iterate till the length of the string
    for j in range(l):
         
        ans = chr(p + j % y)
        print(ans, end ="")
         
 
# Driver code
l = 6
x = 5
y = 3
String(l, x, y)

C#

// C# implementation to
// construct a string of length L
// such that each substring of length
// X has exactly Y distinct letters.
using System;
 
class GFG {
    static void String(int l, int x, int y)
    {
        // Initialize p equal to the ASCII value of a
        int p = 97;
     
        // Iterate till the length of the string
        for(int j = 0; j < l; j++)
        {
            char ans = (char)(p + (j % y));
            Console.Write(ans);
        }
    }
     
    // Driver code
    public static void Main(string[] args)
    {
        int l = 6;
        int x = 5;
        int y = 3;
        String(l, x, y);
    }
}
 
// This code is contributed by AnkitRai01

Javascript

 
// javascript implementation to
// construct a string of length L
// such that each substring of length
// X has exactly Y distinct letters.
 
         
function string(l , x , y){
     
    // Initialize p equal to the ASCII value of a
    var p = 97;
 
    // Iterate till the length of the string
    for(var j = 0; j < l ; j++){
         
        var ans = String.fromCharCode(p + (j % y));
        document.write(ans);
    }
         
}
 
// Driver code
var l = 6;
var x = 5;
var y = 3;
string(l, x, y) ;
 
// This code contributed by shikhasingrajput

输出：

abcabc

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