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📜  给定元素数量的(不同顺序的)矩阵计数

📅  最后修改于: 2021-06-25 14:18:01             🧑  作者: Mango

给定数字N表示矩阵中元素的总数,任务是打印矩阵的所有可能顺序。顺序是一对(m,n)整数,其中m是行数,n是列数。例如,如果元素数为8,则所有可能的顺序为:
(1、8),(2、4),(4、2),(8、1)。
例子:

方法:
如果矩阵具有m行和n列,则称其为mxn阶。矩阵中元素的总数等于(m * n)。因此,我们从1开始并逐一检查是否除以N(元素总数)。如果它分裂,它将是一种可能的顺序。
下面是上述方法的实现:

C++
// C++ implementation of the above approach
#include 
using namespace std;
 
// Function to print all possible order
void printAllOrder(int n)
{
    // total number of elements in a matrix
    // of order m * n is equal (m*n)
    // where m is number of rows and n is
    // number of columns
    for (int i = 1; i <= n; i++) {
 
        // if n is divisible by i then i
        // and n/i will be the one
        // possible order of the matrix
        if (n % i == 0) {
 
            // print the given format
            cout << i << " " << n / i << endl;
        }
    }
}
 
// Driver code
int main()
{
    int n = 10;
    printAllOrder(n);
    return 0;
}


Java
// Java implementation of the above approach
 
 
class GFG
    {
    // Function to print all possible order
    static void printAllOrder(int n)
    {
        // total number of elements in a matrix
        // of order m * n is equal (m*n)
        // where m is number of rows and n is
        // number of columns
        for (int i = 1; i <= n; i++) {
     
            // if n is divisible by i then i
            // and n/i will be the one
            // possible order of the matrix
            if (n % i == 0) {
     
                // print the given format
                System.out.println( i + " " + n / i );
            }
        }
    }
     
    // Driver code
    public static void main(String []args)
    {
        int n = 10;
        printAllOrder(n);
         
    }
 
}
 
 
// This code is contributed by ihritik


Python
# Python implementation of the above approach
 
# Function to print all possible order
def printAllOrder(n):
 
    # total number of elements in a matrix
    # of order m * n is equal (m*n)
    # where m is number of rows and n is
    # number of columns
    for i in range(1,n+1):
 
        # if n is divisible by i then i
        # and n/i will be the one
        # possible order of the matrix
        if (n % i == 0) :
 
            # print the given format
            print( i ,n // i )
         
     
 
 
# Driver code
n = 10
printAllOrder(n)
 
 
# This code is contributed by ihritik


C#
// C# implementation of the above approach
 
using System;
class GFG
    {
    // Function to print all possible order
    static void printAllOrder(int n)
    {
        // total number of elements in a matrix
        // of order m * n is equal (m*n)
        // where m is number of rows and n is
        // number of columns
        for (int i = 1; i <= n; i++) {
     
            // if n is divisible by i then i
            // and n/i will be the one
            // possible order of the matrix
            if (n % i == 0) {
     
                // print the given format
                Console.WriteLine( i + " " + n / i );
            }
        }
    }
     
    // Driver code
    public static void Main()
    {
        int n = 10;
        printAllOrder(n);
         
    }
 
}
 
// This code is contributed by ihritik


PHP


Javascript


输出:
1 10
2 5
5 2
10 1

时间复杂度: O(n)

辅助空间: O(1)