C剪刀石头布

剪刀石头布(也称为石头剪刀布)是一种手工游戏，在两个人之间玩，每个玩家同时形成三种形状中的一种。游戏的获胜者是根据以下规则决定的：

• 摇滚vs纸->纸胜。
• 岩石vs剪刀->岩石获胜。
• 纸vs剪->剪胜。

在该游戏中，将要求用户做出选择，并根据用户和计算机的选择，然后将结果与计算机和用户的选择一起显示。

方法：下面是程序中需要实现的功能：

main()函数：

• 它由变量的声明组成。
• printf()和scanf()函数用于显示内容并从用户那里获取输入。它还包含两个预定义的功能：
  • srand()和rand()用于生成[0，RAND_MAX)和srand()范围内的随机数，尤其有助于每次生成一个随机数。
  • 取用100生成的随机数取模，使其范围在(0到100)之间。
  • 由于范围最多只有100个，因此所有选项(例如石头，纸张和剪刀)之间的分布相等，因为所有选项都有相等的出现概率。

Note: This random number will decide the choice of computer as:

• If the number is between 0-33 then the choice will be Stone.
• If the number is between 33-66 then the choice will be Paper.
• If the number is between 66-100 then the choice will be Scissors.

game()函数：此函数由if-else语句组成，该语句将比较用户和计算机的选择。如果用户获胜，则它将返回1 。否则，如果计算机获胜，它将返回0 。如果是平局，则将返回-1 。

下面是上述方法的实现：

C

// C program for the above approach
#include 
#include 
#include 
  
// Function to implement the game
int game(char you, char computer)
{
    // If both the user and computer
    // has chose the same thing
    if (you == computer)
        return -1;
  
    // If user's choice is stone and
    // computer's choice is paper
    if (you == 's' && computer == 'p')
        return 0
  
            // If user's choice is paper and
            // computer's choice is stone
            else if (you == 'p' && computer == 's') return 1;
  
    // If user's choice is stone and
    // computer's choice is scissor
    if (you == 's' && computer == 'z')
        return 1;
  
    // If user's choice is scissor and
    // computer's choice is stone
    else if (you == 'z' && computer == 's')
        return 0;
  
    // If user's choice is paper and
    // computer's choice is scissor
    if (you == 'p' && computer == 'z')
        return 0;
  
    // If user's choice is scissor and
    // computer's choice is paper
    else if (you == 'z' && computer == 'p')
        return 1;
}
  
// Driver Code
int main()
{
    // Stores the random number
    int n;
  
    char you, computer, result;
  
    // Chooses the random number
    // every time
    srand(time(0));
  
    // Make the random number less
    // than 100, divided it by 100
    n = rand() % 100;
  
    // Using simple probability 100 is
    // roughly divided among stone,
    // paper, and scissor
    if (n < 33)
  
        // s is denoting Stone
        computer = 's';
  
    else if (n > 33 && n < 66)
  
        // p is denoting Paper
        computer = 'p';
  
    // z is denoting Scissor
    else
        computer = 'z';
  
    printf("\n\n\n\n\t\t\t\tEnter s "
           "for STONE, p for PAPER "
           "and z for SCISSOR\n\t\t\"
           "t\t\t\t\t");
  
    // input from the user
    scanf("%c", &you);
  
    // Function Call to play the game
    result = game(you, computer);
  
    if (result == -1) {
        printf("\n\n\t\t\t\tGame Draw!\n");
    }
    else if (result == 1) {
        printf("\n\n\t\t\t\tWow! "
               "You have won the game!\n");
        else printf("\n\n\t\t\t\tOh! You "
                    "have lost the game!\n");
  
        printf("\t\t\t\tYOu choose : %c"
               " and Computer choose : "
               "%c\n",
               you, computer);
  
        return 0;
    }

输出：

• 首先，将询问用户有关选择：

• 当用户输入选项时，将显示结果：

想要从精选的最佳视频中学习和练习问题，请查看《基础知识到高级C的C基础课程》。