实现剪刀石头布游戏的Python程序

Python是一种多用途语言，可以用它做任何事情。 Python也可用于游戏开发。让我们在不使用任何外部游戏库（如 PyGame）的情况下创建一个简单的命令行 Rock-Paper-Scissor 游戏。
在这个游戏中，用户第一次有机会在石头、纸和剪刀中进行选择。在该计算机从剩余的两个选项中（随机）选择之后，根据规则决定获胜者。

Winning Rules as follows :

Rock vs paper-> paper wins
Rock vs scissor-> Rock wins
paper vs scissor-> scissor wins.

在这个游戏中，randint() 内置函数用于生成给定范围内的随机整数值。
下面是实现：

Python3

# import random module
import random
 
# Print multiline instruction
# performstring concatenation of string
print("Winning Rules of the Rock paper scissor game as follows: \n"
                                +"Rock vs paper->paper wins \n"
                                + "Rock vs scissor->Rock wins \n"
                                +"paper vs scissor->scissor wins \n")
 
while True:
    print("Enter choice \n 1 for Rock, \n 2 for paper, and \n 3 for scissor \n")
     
    # take the input from user
    choice = int(input("User turn: "))
 
    # OR is the short-circuit operator
    # if any one of the condition is true
    # then it return True value
     
    # looping until user enter invalid input
    while choice > 3 or choice < 1:
        choice = int(input("enter valid input: "))
         
 
    # initialize value of choice_name variable
    # corresponding to the choice value
    if choice == 1:
        choice_name = 'Rock'
    elif choice == 2:
        choice_name = 'paper'
    else:
        choice_name = 'scissor'
         
    # print user choice
    print("user choice is: " + choice_name)
    print("\nNow its computer turn.......")
 
    # Computer chooses randomly any number
    # among 1 , 2 and 3. Using randint method
    # of random module
    comp_choice = random.randint(1, 3)
     
    # looping until comp_choice value
    # is equal to the choice value
    while comp_choice == choice:
        comp_choice = random.randint(1, 3)
 
    # initialize value of comp_choice_name
    # variable corresponding to the choice value
    if comp_choice == 1:
        comp_choice_name = 'Rock'
    elif comp_choice == 2:
        comp_choice_name = 'paper'
    else:
        comp_choice_name = 'scissor'
         
    print("Computer choice is: " + comp_choice_name)
 
    print(choice_name + " V/s " + comp_choice_name)
 
    # condition for winning
    if((choice == 1 and comp_choice == 2) or
      (choice == 2 and comp_choice ==1 )):
        print("paper wins => ", end = "")
        result = "paper"
         
    elif((choice == 1 and comp_choice == 3) or
        (choice == 3 and comp_choice == 1)):
        print("Rock wins =>", end = "")
        result = "Rock"
    else:
        print("scissor wins =>", end = "")
        result = "scissor"
 
    # Printing either user or computer wins
    if result == choice_name:
        print("<== User wins ==>")
    else:
        print("<== Computer wins ==>")
         
    print("Do you want to play again? (Y/N)")
    ans = input()
 
 
    # if user input n or N then condition is True
    if ans == 'n' or ans == 'N':
        break
     
# after coming out of the while loop
# we print thanks for playing
print("\nThanks for playing")

输出 ：

winning Rules of the Rock paper and scissor game as follows:
rock vs paper->paper wins 
rock vs scissors->rock wins 
paper vs scissors->scissors wins 

Enter choice 
 1. Rock 
 2. paper 
 3. scissor 

User turn: 1
User choice is: Rock

Now its computer turn.......

computer choice is: paper
Rock V/s paper
paper wins =>computer wins
do you want to play again?
N