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📜  从除相同索引的元素以外的所有元素的XOR数组构造以K开头的原始数组

📅  最后修改于: 2021-05-06 19:16:27             🧑  作者: Mango

给定一个由N个整数组成的数组A []并且数组B []的第一个元素为K ,任务是从A []构造数组B [] ,使得对于任何索引iA [i]都是按位的B []B [i]之外的所有数组元素的XOR。

例子:

方法:这个想法是基于观察到的相同值偶数计算的按位XOR为0

请按照以下步骤解决问题:

  • 将数组B []中存在的所有元素的按位XOR存储在一个变量中,例如totalXOR ,其中totalXOR = A [0] ^ K。
  • 遍历每个数组元素A [i]的给定数组A [] ,将B [i]的值存储为totalXOR ^ A [i]
  • 完成上述步骤后,打印存储在数组B []中的元素。

下面是上述方法的实现:

C++
// C++ program for the above aproach
#include 
using namespace std;
 
// Function to construct an array
// with each element equal to XOR
// of all array elements except
// the element at the same index
void constructArray(int A[], int N,
                    int K)
{
    // Original array
    int B[N];
 
    // Stores Bitwise XOR of array
    int totalXOR = A[0] ^ K;
 
    // Calculate XOR of all array elements
    for (int i = 0; i < N; i++)
        B[i] = totalXOR ^ A[i];
 
    // Print the original array B[]
    for (int i = 0; i < N; i++) {
        cout << B[i] << " ";
    }
}
 
// Driver Code
int main()
{
    int A[] = { 13, 14, 10, 6 }, K = 2;
    int N = sizeof(A) / sizeof(A[0]);
 
    // Function Call
    constructArray(A, N, K);
 
    return 0;
}


Java
// Java program for the above aproach
class GFG{
     
// Function to construct an array
// with each element equal to XOR
// of all array elements except
// the element at the same index
static void constructArray(int A[], int N,
                           int K)
{
     
    // Original array
    int B[] = new int[N];
   
    // Stores Bitwise XOR of array
    int totalXOR = A[0] ^ K;
   
    // Calculate XOR of all array elements
    for(int i = 0; i < N; i++)
        B[i] = totalXOR ^ A[i];
   
    // Print the original array B[]
    for(int i = 0; i < N; i++)
    {
        System.out.print(B[i] + " ");
    }
}
 
// Driver Code
public static void main(String[] args)
{
    int A[] = { 13, 14, 10, 6 }, K = 2;
    int N = A.length;
     
    // Function Call
    constructArray(A, N, K);
}
}
 
// This code is contributed by divyeshrabadiya07


Python3
# Python program for the above aproach
 
# Function to construct an array
# with each element equal to XOR
# of all array elements except
# the element at the same index
def constructArray(A, N, K):
   
    # Original array
    B = [0] * N;
 
    # Stores Bitwise XOR of array
    totalXOR = A[0] ^ K;
 
    # Calculate XOR of all array elements
    for i in range(N):
        B[i] = totalXOR ^ A[i];
 
    # Prthe original array B
    for i in range(N):
        print(B[i], end = " ");
 
# Driver Code
if __name__ == '__main__':
    A = [13, 14, 10, 6];
    K = 2;
    N = len(A);
 
    # Function Call
    constructArray(A, N, K);
 
# This code is contributed by Princi Singh


C#
// C# program for the above aproach
using System;
using System.Collections;
class GFG {
     
    // Function to construct an array
    // with each element equal to XOR
    // of all array elements except
    // the element at the same index
    static void constructArray(int[] A, int N,
                               int K)
    {
          
        // Original array
        int[] B = new int[N];
        
        // Stores Bitwise XOR of array
        int totalXOR = A[0] ^ K;
        
        // Calculate XOR of all array elements
        for(int i = 0; i < N; i++)
            B[i] = totalXOR ^ A[i];
        
        // Print the original array B[]
        for(int i = 0; i < N; i++)
        {
            Console.Write(B[i] + " ");
        }
    }
 
  static void Main() {
    int[] A = { 13, 14, 10, 6 };
    int K = 2;
    int N = A.Length;
      
    // Function Call
    constructArray(A, N, K);
  }
}
 
// This code is contributed by divyesh072019


Javascript


输出:
2 1 5 9

时间复杂度: O(N)
辅助空间: O(1)