Python中的 numpy.mod()

numpy.mod()是在 numpy 中进行数学运算的另一个函数。它返回两个数组 arr1 和 arr2 之间除法的元素余数，即arr1 % arr2 。当 arr2 为 0 并且 arr1 和 arr2 都是（数组) 整数。

Syntax : numpy.mod(arr1, arr2, /, out=None, *, where=True, casting=’same_kind’, order=’K’, dtype=None, subok=True[, signature, extobj], ufunc ‘remainder’)

Parameters :
arr1 : [array_like] Dividend array.
arr2 : [array_like] Divisor array.
dtype : The type of the returned array. By default, the dtype of arr is used.
out : [ndarray, optional] A location into which the result is stored.
  -> If provided, it must have a shape that the inputs broadcast to.
  -> If not provided or None, a freshly-allocated array is returned.
where : [array_like, optional] Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone.
**kwargs : Allows to pass keyword variable length of argument to a function. Used when we want to handle named argument in a function.

Return : [ndarray] The element-wise remainder i.e arr1 % arr2 .

代码#1：

# Python program explaining
# numpy.mod() function
  
import numpy as geek
in_num1 = 6
in_num2 = 4
  
print ("Dividend : ", in_num1)
print ("Divisor : ", in_num2)
    
out_num = geek.mod(in_num1, in_num2) 
print ("Remainder : ", out_num) 

输出 ：

Dividend :  6
Divisor :  4
Remainder :  2

代码#2：

# Python program explaining
# numpy.mod() function
  
import numpy as geek
  
in_arr1 = geek.array([2, -4, 7])
in_arr2 = geek.array([2, 3, 4])
   
print ("Dividend array : ", in_arr1)
print ("Divisor array : ", in_arr2)
   
    
out_arr = geek.mod(in_arr1, in_arr2) 
print ("Output remainder array: ", out_arr) 

输出 ：

Dividend array :  [ 2 -4  7]
Divisor array :  [2 3 4]
Output remainder array:  [0 2 3]