Python – 从字符串中删除索引范围

给定一个字符串和范围列表，删除范围中出现的所有字符。

Input : test_str = ‘geeksforgeeks is best for geeks’, range_list = [(3, 6), (7, 10)]
Output : geeks is best for geeks
Explanation : The required ranges removed.

Input : test_str = ‘geeksforgeeks is best for geeks’, range_list = [(3, 6)]
Output : georgeeks is best for geeks
Explanation : The required ranges removed.

方法#1：使用循环

在此，我们检查每个范围，重新制作字符串，考虑到索引不在于使用条件语句进行范围检查。

Python3

# Python3 code to demonstrate working of 
# Remove index ranges from String 
# Using loop
  
# initializing strings
test_str1 = 'geeksforgeeks is best for geeks'
  
# printing original string
print("The original string 1 is : " + str(test_str1))
  
# initializing ranges list 
range_list = [(3, 6), (7, 10), (14, 17)]
  
res = ""
  
for idx, chr in enumerate(test_str1):
  for strt_idx, end_idx in range_list:
        
    # checking for ranges and appending 
    if strt_idx <= idx + 1 <= end_idx: 
      break
  else:
    res += chr
  
# printing result 
print("The reconstructed string : " + str(res))

输出

The original string 1 is : geeksforgeeks is best for geeks
The reconstructed string : geeksbest for geeks

方法 #2：使用 any() + 列表理解 + join()

在此，我们使用 any() 执行检查字符串索引的任务，并使用列表推导相应地重构字符串。

Python3

# Python3 code to demonstrate working of 
# Remove index ranges from String 
# Using any() + list comprehension + join()
  
# initializing strings
test_str1 = 'geeksforgeeks is best for geeks'
  
# printing original string
print("The original string 1 is : " + str(test_str1))
  
# initializing ranges list 
range_list = [(3, 6), (7, 10), (14, 17)]
  
# using any() to check for strings in index ranges
res = ''.join(chr for idx, chr in enumerate(test_str1, 1) if not any(strt_idx <= idx <= end_idx 
         for strt_idx, end_idx in range_list))
  
# printing result 
print("The reconstructed string : " + str(res)) 

输出

The original string 1 is : geeksforgeeks is best for geeks
The reconstructed string : geeksbest for geeks