SymPy | Python中的 Permutation.next_trotterjohnson()

Permutation.next_trotterjohnson() ：next_trotterjohnson()是一个 sympy Python库函数，它以 Trotter-Johnson 顺序返回下一个排列。如果 self 是最后一个排列，则返回 None。

Syntax : sympy.combinatorics.permutations.Permutation.next_trotterjohnson()

Return : next permutation in Trotter-Johnson order

代码 #1：next_trotterjohnson() 示例

# Python code explaining
# SymPy.Permutation.next_trotterjohnson()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from 
# sympy.combinatorics.permutations.Permutation.next_trotterjohnson() method 
  
# creating Permutation
a = Permutation([[2, 0], [3, 1]])
  
b = Permutation([1, 3, 5, 4, 2, 0])
  
  
print ("Permutation a - next_trotterjohnson form : ", a.next_trotterjohnson())
print ("Permutation b - next_trotterjohnson form : ", b.next_trotterjohnson())

输出 ：

Permutation a – next_trotterjohnson form : (0 3 1 2)
Permutation b – next_trotterjohnson form : (0 1 5)(2 3 4)

代码 #2：next_trotterjohnson() 示例– 2D 排列

# Python code explaining
# SymPy.Permutation.next_trotterjohnson()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from 
# sympy.combinatorics.permutations.Permutation.next_trotterjohnson() method 
  
# creating Permutation
a = Permutation([[2, 4, 0], 
                 [3, 1, 2],
                 [1, 5, 6]])
  
  
print ("Permutation a - next_trotterjohnson form : ", a.next_trotterjohnson())

输出 ：

Permutation a – next_trotterjohnson form : (6)(0 3 5 1 2 4)