📜  Python - 每个键的唯一值计数

📅  最后修改于: 2022-05-13 01:55:45.331000             🧑  作者: Mango

Python - 每个键的唯一值计数

给定一个字典列表,任务是编写一个Python程序来计算每个键的唯一值。

例子:

方法 #1:使用len() + set() + 循环

在这种情况下,使用 set() 提取唯一值,使用 len() 获取其计数,然后将结果映射到使用 keys() 提取的每个键。迭代键发生在循环中。

Python3
# Python3 code to demonstrate working of
# Unique values count of each Key
# Using len() + set()
  
# initializing lists
test_list = [{"gfg": 1, "is": 3, "best": 2}, {
    "gfg": 1, "is": 3, "best": 6}, {"gfg": 7, "is": 3, "best": 10}]
  
# printing original list
print("The original list is : " + str(test_list))
  
res = dict()
for key in test_list[0].keys():
  
    # mapping unique values.
    res[key] = len(set([sub[key] for sub in test_list]))
  
# printing result
print("Unique count of keys : " + str(res))


Python3
# Python3 code to demonstrate working of
# Unique values count of each Key
# Using len() + set() + dictionary comprehension
  
# initializing lists
test_list = [{"gfg": 1, "is": 3, "best": 2}, {
    "gfg": 1, "is": 3, "best": 6}, {"gfg": 7, "is": 3, "best": 10}]
  
# printing original list
print("The original list is : " + str(test_list))
  
# dictionary comprehension for compact solution
res = {key: len(set([sub[key] for sub in test_list]))
       for key in test_list[0].keys()}
  
# printing result
print("Unique count of keys : " + str(res))


输出:

方法 #2:使用字典理解 + len() + set()

与上述方法类似,不同之处在于字典理解被用作速记的一种线性替代方法。

蟒蛇3

# Python3 code to demonstrate working of
# Unique values count of each Key
# Using len() + set() + dictionary comprehension
  
# initializing lists
test_list = [{"gfg": 1, "is": 3, "best": 2}, {
    "gfg": 1, "is": 3, "best": 6}, {"gfg": 7, "is": 3, "best": 10}]
  
# printing original list
print("The original list is : " + str(test_list))
  
# dictionary comprehension for compact solution
res = {key: len(set([sub[key] for sub in test_list]))
       for key in test_list[0].keys()}
  
# printing result
print("Unique count of keys : " + str(res))

输出: