Python – N 维中的相邻坐标

有时，在使用Python Matrix 时，我们可能会遇到需要提取给定坐标的所有相邻坐标的问题。这种问题可以在许多领域都有应用，例如网络开发和学校编程。让我们讨论可以执行此任务的特定方式。

Input : test_tup = (1, 2, 3)
Output : [[0, 1, 2], [0, 1, 3], [0, 1, 4], [0, 2, 2], [0, 2, 3], [0, 2, 4], [0, 3, 2], [0, 3, 3], [0, 3, 4], [1, 1, 2], [1, 1, 3], [1, 1, 4], [1, 2, 2], [1, 2, 3], [1, 2, 4], [1, 3, 2], [1, 3, 3], [1, 3, 4], [2, 1, 2], [2, 1, 3], [2, 1, 4], [2, 2, 2], [2, 2, 3], [2, 2, 4], [2, 3, 2], [2, 3, 3], [2, 3, 4]]
Input : test_tup = (5, 6)
Output : [[4, 5], [4, 6], [4, 7], [5, 5], [5, 6], [5, 7], [6, 5], [6, 6], [6, 7]]

方法：使用递归+ yield
上述功能的组合可以用来解决这个问题。在此，我们对查询坐标周围的坐标使用 yield 动态提取元素，并使用递归处理下一列和下一行。

# Python3 code to demonstrate working of 
# Adjacent Coordinates in N dimension
# Using recursion + yield
  
# helper_fnc
def adjac(ele, sub = []):
  if not ele:
     yield sub
  else:
     yield from [idx for j in range(ele[0] - 1, ele[0] + 2)
                for idx in adjac(ele[1:], sub + [j])]
  
# initializing tuple
test_tup = (3, 4)
  
# printing original tuple
print("The original tuple : " + str(test_tup))
  
# Initialize dictionary keys with Matrix
# Using deepcopy()
res = list(adjac(test_tup))
  
# printing result 
print("The adjacent Coordinates : " + str(res)) 

输出 ：

The original tuple : (3, 4)
The adjacent Coordinates : [[2, 3], [2, 4], [2, 5], [3, 3], [3, 4], [3, 5], [4, 3], [4, 4], [4, 5]]