泛数字产品

Pandigital Number是一个数字，它仅使用一次数字1到9。给定一个数字，我们需要确定是否有两个数字的乘积是给定的数字，而给定的三个数字加在一起就是泛数字。

例子：

Input : 7254
Output : Yes
39 * 186 = 7254. We can notice that
the three numbers 39, 186 and 7254
together have all digits from 1 to 9.

Input : 6952
Output : Yes

想法是考虑所有乘以给定数的对。对于每对，创建一个包含三个数字(给定数字和当前对)的字符串。我们对创建的字符串排序，并检查排序后的字符串是否等于“ 123456789”。

C++

// C++ code to check the number
// is Pandigital Product or not
#include 
using namespace std;
 
// To check the string formed
// from multiplicand, multiplier
// and product is pandigital
bool isPandigital(string str)
{
    if (str.length() != 9)
        return false;
     
    char ch[str.length()];
    strcpy(ch, str.c_str());
    sort(ch, ch + str.length());
    string s = ch;
     
    if(s.compare("123456789") == 0)
        return true;
    else
        return true;
}
 
// calculate the multiplicand,
// multiplier, and product
// eligible for pandigital
bool PandigitalProduct_1_9(int n)
{
    for (int i = 1; i * i <= n; i++)
        if (n % i == 0 && isPandigital(to_string(n) +
                                       to_string(i) +
                                   to_string(n / i)))
            return true;
    return false;
}
 
// Driver Code
int main()
{
    int n = 6952;
    if (PandigitalProduct_1_9(n) == true)
        cout << "yes";
    else
        cout << "no";
    return 0;
}
 
// This code is contributed by
// Manish Shaw(manishshaw1)

Java

// Java code to check the number
// is Pandigital Product or not
import java.io.*;
import java.util.*;
class GFG {
 
    // calculate the multiplicand, multiplier, and product
    // eligible for pandigital
    public static boolean PandigitalProduct_1_9(int n)
    {
        for (int i = 1; i*i <= n; i++)
            if (n % i == 0 && isPandigital("" + n + i + n / i))
                return true;
        return false;
    }
 
    // To check the string formed from multiplicand
    // multiplier and product is pandigital
    public static boolean isPandigital(String str)
    {
        if (str.length() != 9)
            return false;
        char ch[] = str.toCharArray();
        Arrays.sort(ch);
        return new String(ch).equals("123456789");
    }
 
    // Driver function
    public static void main(String[] args)
    {
        int n = 6952;
        if (PandigitalProduct_1_9(n) == true)
            System.out.println("yes");
        else
            System.out.println("no");
    }
}

Python3

# Python3 code to check the number
# is Pandigital Product or not
 
# Calculate the multiplicand,
# multiplier, and product
# eligible for pandigital
def PandigitalProduct_1_9(n):
     
    i = 1
    while i * i <= n:
         
        if ((n % i == 0) and
             bool(isPandigital(str(n) +
                               str(i) +
                               str(n // i)))):
            return bool(True)
             
        i += 1
     
    return bool(False)
 
# To check the string formed from
# multiplicand multiplier and
# product is pandigital
def isPandigital(Str):
 
    if (len(Str) != 9):
        return bool(False)
         
    ch = "".join(sorted(Str))
     
    if (ch == "123456789"):
        return bool(True)
    else:
        return bool(False)
 
# Driver code
n = 6952
if (bool(PandigitalProduct_1_9(n))):
    print("yes")
else:
    print("no")
 
# This code is contributed by divyeshrabadiya07

C#

// C# code to check the number
// is Pandigital Product or not.
using System;
 
class GFG {
 
    // calculate the multiplicand,
    // multiplier, and product
    // eligible for pandigital
    public static bool PandigitalProduct_1_9(int n)
    {
        for (int i = 1; i*i <= n; i++)
            if (n % i == 0 && isPandigital("" + n
                                      + i + n / i))
                return true;
                 
        return false;
    }
 
    // To check the string formed from multiplicand
    // multiplier and product is pandigital
    public static bool isPandigital(String str)
    {
        if (str.Length != 9)
            return false;
             
        char []ch = str.ToCharArray();
        Array.Sort(ch);
         
        return new String(ch).Equals("123456789");
    }
 
    // Driver function
    public static void Main()
    {
        int n = 6952;
         
        if (PandigitalProduct_1_9(n) == true)
            Console.Write("yes");
        else
            Console.Write("no");
    }
}
 
// This code is contributed by nitin mittal.

输出：

yes