📜  检查数字是否为Quartan Prime

📅  最后修改于: 2021-04-22 06:13:47             🧑  作者: Mango

给定正整数N,请检查它是否为Quartan素数。如果是Quartan素数,则打印“是”,否则打印“否”。

Quartan素数:形式为x 4 + y 4的素数(其中x> 0,y> 0且x和y是整数)是Quartan素数。

Quartan Prime的范围是1 – 100:

例子

Input : 17
Output : Yes
Explanation : 17 is a prime number and can be
expressed in the form of:
x4 + y4  as ( 14 + 24 )

Input : 31
Output : No
Explanation: 31 is prime number but can not be
expressed in the form of x4 + y4.

一个简单的解决方案是检查给定的数字是否为质数,然后检查其是否可以x 4 + y 4的形式表示。

一个有效的解决方案基于以下事实:每个Quartan Prime也可以以16 * n + 1的形式表示。因此,我们可以检查数字是否为质数,是否可以以16 * n +1的形式表示。如果是,则该数字为Quartan Prime,否则为。

下面是上述方法的实现

C++
// CPP program to check if a number is
// Quartan Prime or not
  
#include 
using namespace std;
  
// Function to check if a number
// is prime or not
bool isPrime(int n)
{
    // Corner cases
    if (n <= 1)
        return false;
    if (n <= 3)
        return true;
  
    // This is checked so that we can skip
    // middle five numbers in below loop
    if (n % 2 == 0 || n % 3 == 0)
        return false;
  
    for (int i = 5; i * i <= n; i = i + 6) {
        if (n % i == 0 || n % (i + 2) == 0) {
            return false;
        }
    }
    return true;
}
  
// Driver Program
int main()
{
    int n = 17;
  
    // Check if number is prime
    // and of the form 16*n + 1
    if (isPrime(n) && (n % 16 == 1)) {
        cout << "YES";
    }
    else {
        cout << "NO";
    }
  
    return 0;
}


Java
// JAVA program to check if a number is
// Quartan Prime or not
  
class GFG {
  
    // Function to check if a number 
    // is prime or not
    static boolean isPrime(int n)
    {
        // Corner cases
        if (n <= 1)
            return false;
        if (n <= 3)
            return true;
  
        // This is checked so that we can skip
        // middle five numbers in below loop
        if (n % 2 == 0 || n % 3 == 0)
            return false;
  
        for (int i = 5; i * i <= n; i = i + 6) {
            if (n % i == 0 || n % (i + 2) == 0) {
                return false;
            }
        }
        return true;
    }
  
    // Driver Program
    public static void main(String[] args)
    {
        int n = 17;
  
        // Check if number is prime
        // and of the form 16*n + 1
        if (isPrime(n) && (n % 16 == 1)) {
            System.out.println("YES");
        }
        else {
            System.out.println("NO");
        }
    }
}


Python3
# Python 3 program to check if a number is 
# Quartan Prime or not
  
# Utility function to check
# if a number is prime or not
def isPrime(n) : 
    # Corner cases 
    if (n <= 1) : 
        return False
    if (n <= 3) : 
        return True
    
    # This is checked so that we can skip  
    # middle five numbers in below loop 
    if (n % 2 == 0 or n % 3 == 0) : 
        return False
    
    i = 5
    while(i * i <= n) : 
        if (n % i == 0 or n % (i + 2) == 0) : 
            return False
        i = i + 6
    
    return True
            
# Driver Code 
n = 17
      
# Check if number is prime 
# and of the form 16 * n + 1
  
if(isPrime(n) and (n % 16 == 1) ):
  
    print("YES")
  
else:
  
    print("NO")


C#
// C# program to check if a number 
// is Quartan Prime or not
using System;
  
class GFG 
{
  
// Function to check if a number 
// is prime or not
static bool isPrime(int n)
{
    // Corner cases
    if (n <= 1)
        return false;
    if (n <= 3)
        return true;
  
    // This is checked so that we 
    // can skip middle five numbers 
    // in below loop
    if (n % 2 == 0 || n % 3 == 0)
        return false;
  
    for (int i = 5; i * i <= n; i = i + 6) 
    {
        if (n % i == 0 || n % (i + 2) == 0)
        {
            return false;
        }
    }
    return true;
}
  
// Driver Code
public static void Main()
{
    int n = 17;
  
    // Check if number is prime
    // and of the form 16*n + 1
    if (isPrime(n) && (n % 16 == 1)) 
    {
        Console.WriteLine("YES");
    }
    else 
    {
        Console.WriteLine("NO");
    }
}
}
  
// This code is contributed
// by inder_verma


PHP


输出:
YES