Python - 具有特定字母的字数

给定字符串单词，提取具有特定字母的单词数。

Input : test_str = ‘geeksforgeeks is best for geeks’, letter = “g”
Output : 2
Explanation : “g” occurs in 2 words.

Input : test_str = ‘geeksforgeeks is best for geeks’, letter = “s”
Output : s
Explanation : “s” occurs in 4 words.

方法 #1：使用列表推导 + len() + split()

这是可以执行此任务的方法之一。在这里，我们使用 split() 执行从字符串中提取单词的任务，循环用于迭代单词以检查字母是否存在，len() 用于获取带有字母的单词数。

Python3

# Python3 code to demonstrate working of 
# Count of Words with specific letter
# Using list comprehension + len() + split()
  
# initializing string
test_str = 'geeksforgeeks is best for geeks'
  
# printing original string
print("The original string is : " + str(test_str))
  
# initializing letter 
letter = "e"
  
# extracting desired count using len()
# list comprehension is used as shorthand
res = len([ele for ele in test_str.split() if letter in ele])
  
# printing result 
print("Words count : " + str(res))

输出

The original string is : geeksforgeeks is best for geeks
Words count : 3

方法 #2：使用 filter() + lambda + len() + split()

这是可以执行此任务的另一种方式。在此，我们使用 filter() + lambda 执行过滤任务。

蟒蛇3

# Python3 code to demonstrate working of 
# Count of Words with specific letter
# Using filter() + lambda + len() + split()
  
# initializing string
test_str = 'geeksforgeeks is best for geeks'
  
# printing original string
print("The original string is : " + str(test_str))
  
# initializing letter 
letter = "e"
  
# extracting desired count using len()
# filter() used to check for letter existence
res = len(list(filter(lambda ele : letter in ele, test_str.split())))
  
# printing result 
print("Words count : " + str(res)) 

输出

The original string is : geeksforgeeks is best for geeks
Words count : 3