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📜  由每个元素与给定数组中最大元素的差异形成的数组

📅  最后修改于: 2022-05-13 01:57:06.108000             🧑  作者: Mango

由每个元素与给定数组中最大元素的差异形成的数组

给定一个数组arr[] ,任务是找到由每个元素与给定数组中最大元素的差形成的数组。

例子:

方法:
找出数组中 n 个元素中最大的一个,并将其存储在一个变量 maximum。现在检查数组中最大元素和其他元素之间的差异。

下面是上述方法的实现:

C++
// C++ program to find the array formed
// from the difference of each element
// from the largest element in the given array
 
#include 
using namespace std;
int difference(int arr[], int n)
{
    // Initializing current largest
    // as the first element.
    int largest = arr[0];
    int i;
 
    // For loop to compute
    // the largest element
    for (i = 0; i < n; i++) {
 
        // Checking if the current element
        // is greater than the defined largest
        if (largest < arr[i])
            largest = arr[i];
    }
 
    // For loop to replace the elements
    // in the array with the difference
    for (i = 0; i < n; i++)
        arr[i] = largest - arr[i];
 
    // For loop to print the elements
    for (i = 0; i < n; i++)
        cout << arr[i] << " ";
}
 
// Driver code
int main()
{
    int arr[] = { 10, 5, 9, 3, 2 };
    int n = sizeof(arr) / sizeof(arr[0]);
    difference(arr, n);
    return 0;
}


Java
// Java program to find the array formed
// from the difference of each element
// from the largest element in the given array
import java.util.*;
 
class GFG
{
static void difference(int arr[], int n)
{
    // Initializing current largest
    // as the first element.
    int largest = arr[0];
    int i;
 
    // For loop to compute
    // the largest element
    for (i = 0; i < n; i++)
    {
 
        // Checking if the current element
        // is greater than the defined largest
        if (largest < arr[i])
            largest = arr[i];
    }
 
    // For loop to replace the elements
    // in the array with the difference
    for (i = 0; i < n; i++)
        arr[i] = largest - arr[i];
 
    // For loop to print the elements
    for (i = 0; i < n; i++)
        System.out.print(arr[i] + " ");
}
 
// Driver code
public static void main(String[] args)
{
    int arr[] = { 10, 5, 9, 3, 2 };
    int n = arr.length;
    difference(arr, n);
}
}
 
// This code is contributed by 29AjayKumar


Python3
# Python3 program to find the array formed
# from the difference of each element
# from the largest element in the given array
def difference(arr, n):
     
    # Initializing current largest
    # as the first element.
    largest = arr[0];
    i = 0;
 
    # For loop to compute
    # the largest element
    for i in range(n):
 
        # Checking if the current element
        # is greater than the defined largest
        if (largest < arr[i]):
            largest = arr[i];
     
    # For loop to replace the elements
    # in the array with the difference
    for i in range(n):
        arr[i] = largest - arr[i];
 
    # For loop to print the elements
    for i in range(n):
        print(arr[i], end = " ");
 
# Driver code
if __name__ == '__main__':
    arr = [ 10, 5, 9, 3, 2 ];
    n = len(arr);
    difference(arr, n);
 
# This code is contributed by Rajput-Ji


C#
// C# program to find the array formed
// from the difference of each element
// from the largest element in the given array
using System;
 
class GFG
{
     
static void difference(int []arr, int n)
{
    // Initializing current largest
    // as the first element.
    int largest = arr[0];
    int i;
 
    // For loop to compute
    // the largest element
    for (i = 0; i < n; i++)
    {
 
        // Checking if the current element
        // is greater than the defined largest
        if (largest < arr[i])
            largest = arr[i];
    }
 
    // For loop to replace the elements
    // in the array with the difference
    for (i = 0; i < n; i++)
        arr[i] = largest - arr[i];
 
    // For loop to print the elements
    for (i = 0; i < n; i++)
        Console.Write(arr[i] + " ");
}
 
// Driver code
public static void Main(String[] args)
{
    int []arr = { 10, 5, 9, 3, 2 };
    int n = arr.Length;
    difference(arr, n);
}
}
 
// This code is contributed by PrinciRaj1992


Javascript


输出:
0 5 1 7 8