计算字符串中数字和字母个数的Python程序

先决条件： isnumeric() 方法Python

给定一个包含数字和字母的字符串，任务是编写一个Python程序来计算字符串中数字和字母的个数。以下块表达了其背后的基本思想：

Input: string = "geeks2for3geeks"
Output: total digits = 2 and total letters = 13

Input: string = "python1234"
Output: total digits = 4 and total letters = 6

Input: string = "co2mpu1te10rs"
Output: total digits = 4 and total letters = 9

第一种方法

这里的想法是通过遍历所有字符并检查字符是否在 all_digits 或 all_letters 中来解决这个问题。

程序：

Python3

# define all digits as string
all_digits = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
  
# define all letters
all_letters = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l',
               'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
  
# given string
string = "geeks2for3geeks"
  
# intialized value
total_digits = 0
total_letters = 0
  
# iterate through all characters
for s in string:
  
    # if character found in all_digits then increment total_digits by one
    if s in all_digits:
        total_digits += 1
  
    # if character found in all_letters then increment total_letters by one
    elif s in all_letters:
        total_letters += 1
  
print("Total letters found :-", total_letters)
print("Total digits found :-", total_digits)

输出：

Total letters found :- 13
Total digits found :- 2

优化方法

我们可以检查，而不是检查 all_letters 中的字符：

• 如果在所有数字中找到字符，则将 total_digits 值加一
• 如果不是，则表示字符是一个字母，将 total_letters 值加一

程序：

蟒蛇3

# define all digits as string
all_digits = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
  
# define all letters
all_letters = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l',
               'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
  
# given string
string = "geeks2for3geeks"
  
# intialized value
total_digits = 0
total_letters = 0
  
# iterate through all characters
for s in string:
  
    # if character found in all_digits then increment total_digits by one
    if s in all_digits:
        total_digits += 1
  
    # if character not found in all_digits then increment total_letters by one
    else:
        total_letters += 1
  
print("Total letters found :-", total_letters)
print("Total digits found :-", total_digits)

输出：

Total letters found :- 13
Total digits found :- 2

第二种方法（更优化的方法）

这里的想法是通过遍历所有字符并使用 isnumeric()函数检查字符是字母还是数字来解决这个问题。如果 isnumeric 为 True，则表示字符是数字，否则字符是字母。

程序：

蟒蛇3

# given string
string = "python1234"
  
# intialized value
total_digits = 0
total_letters = 0
  
# iterate through all characters
for s in string:
  
    # if character is digit (return True)
    if s.isnumeric():
        total_digits += 1
  
    # if character is letter (return False)
    else:
        total_letters += 1
  
print("Total letters found :-", total_letters)
print("Total digits found :-", total_digits)

输出：

Total letters found :- 6
Total digits found :- 4