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📜  通过反复将其面积减少一半来最大限度地增加纸张数量

📅  最后修改于: 2021-10-26 05:57:36             🧑  作者: Mango

给定两个整数AB ,代表一张纸的长度和宽度,任务是通过重复将面积减半直到它不能被2整除,找到可以从中生成的最大张数。

例子:

处理方法:按照以下步骤解决问题:

  • 计算提供的初始表的总面积。
  • 现在,继续将工作表的面积除以2,直到它变成奇数。
  • 每次除法后,将计数增加到其值的两倍。
  • 最后,打印获得的计数。

下面是上述方法的实现:

C++
// C++ program for the above approach
#include 
using namespace std;
 
// Function to calculate the
// maximum number of sheets
// possible by given operations
int maxSheets(int A, int B)
{
    int area = A * B;
 
    // Initial count of sheets
    int count = 1;
 
    // Keep dividing the
    // sheets into half
    while (area % 2 == 0) {
 
        // Reduce area by half
        area /= 2;
 
        // Increase count by twice
        count *= 2;
    }
 
    return count;
}
 
// Driver Code
int main()
{
 
    int A = 5, B = 10;
    cout << maxSheets(A, B);
 
    return 0;
}


Java
// Java program for the above approach
import java.util.*;
class GFG
{
 
  // Function to calculate the
  // maximum number of sheets
  // possible by given operations
  static int maxSheets(int A, int B)
  {
    int area = A * B;
 
    // Initial count of sheets
    int count = 1;
 
    // Keep dividing the
    // sheets into half
    while (area % 2 == 0)
    {
 
      // Reduce area by half
      area /= 2;
 
      // Increase count by twice
      count *= 2;
    }
    return count;
  }
 
 
  // Driver Code
  public static void main(String args[])
  {
    int A = 5, B = 10;
    System.out.println(maxSheets(A, B));
  }
}
 
// This code is contributed by jana_sayantan.


Python3
# Python program for the above approach
 
# Function to calculate the
# maximum number of sheets
# possible by given operations
def maxSheets( A, B):
    area = A * B
 
    # Initial count of sheets
    count = 1
 
    # Keep dividing the
    # sheets into half
    while (area % 2 == 0):
 
        # Reduce area by half
        area //= 2
 
        # Increase count by twice
        count *= 2
    return count
 
# Driver Code
A = 5
B = 10
print(maxSheets(A, B))
 
# This code is contributed by rohitsingh07052.


C#
// C# program for the above approach
using System;
class GFG
{
 
    // Function to calculate the
    // maximum number of sheets
    // possible by given operations
    static int maxSheets(int A, int B)
    {
        int area = A * B;
 
        // Initial count of sheets
        int count = 1;
 
        // Keep dividing the
        // sheets into half
        while (area % 2 == 0)
        {
 
            // Reduce area by half
            area /= 2;
 
            // Increase count by twice
            count *= 2;
        }
 
        return count;
    }
 
    // Driver Code
    public static void Main()
    {
        int A = 5, B = 10;
        Console.WriteLine(maxSheets(A, B));
    }
}
 
// This code is contributed by chitranayal.


Javascript


输出:
2

时间复杂度: O(log 2 (A * B))
辅助空间: O(1)

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