当给定另一个相同长度的弦所对的角度时，该弦所对的角度

给定一个具有两条等长弦的圆。给出了其中一根弦对中心的对角。这里的任务是找到另一个和弦在中心所对的角度的度量。
例子：

Input: 48
Output: 48 degrees


Input: 82
Output: 82 degrees

方法：
令AC和BD是圆心在O的两个相等的弦。令弦AC所对的角度为x度。
现在，
在三角形AOC和BOD 中，
AO = OB （同圆的半径）
AB = CD （等弦）
OC = OD （同圆的半径）
所以，三角形AOC和BOD彼此全等
所以，角AOC = 角BOD

Equal chords of a circle subtend equal angles at the centre.

下面是上述方法的实现：

C++

// C++ program to find the angle
// subtended at the center by the chord
// when the angle subtended at center
// by another chord of equal length is given
 
#include 
using namespace std;
 
void angleequichord(int z)
{
    cout << "The angle subtended at the center is "
         << z << " degrees" << endl;
}
 
// Driver code
int main()
{
    int z = 48;
    angleequichord(z);
    return 0;
}

Java

// Java program to find the angle
// subtended at the center by the chord
// when the angle subtended at center
// by another chord of equal length is given
 
import java.io.*;
 
class GFG
{
     
static void angleequichord(int z)
{
    System.out.println ( "The angle subtended at the center is "+
        z + " degrees");
}
 
// Driver code
public static void main (String[] args)
{
 
    int z = 48;
    angleequichord(z);
}
}
 
// This code is contributed by ajit.

Python3

# Python3 program to find the angle
# subtended at the center by the chord
# when the angle subtended at center
# by another chord of equal length is given
 
def angleequichord(z) :
 
    print("The angle subtended at",
          "the center is", z ,"degrees" );
 
# Driver code
if __name__ == "__main__" :
     
    z = 48;
    angleequichord(z);
     
# This code is contributed by AnkitRai01

C#

// C# program to find the angle
// subtended at the center by the chord
// when the angle subtended at center
// by another chord of equal length is given
using System;
     
class GFG
{
     
static void angleequichord(int z)
{
    Console.WriteLine( "The angle subtended at the center is "+
        z + " degrees");
}
 
// Driver code
public static void Main (String[] args)
{
 
    int z = 48;
    angleequichord(z);
}
}
 
/* This code contributed by PrinciRaj1992 */

Javascript

// JavaScript program to find the angle
// subtended at the center by the chord
// when the angle subtended at center
// by another chord of equal length is given
  
 
function angleequichord(z)
{
    document.write("The angle subtended at the center is "
        + z + " degrees" + "<br>");
}
 
// Driver code
 
    let z = 48;
    angleequichord(z);
      
// This code is contributed by Surbhi Tyagi.
 

输出：

The angle subtended at the center is 48 degrees

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