📜  检查矩阵的行主序路径是否为回文

📅  最后修改于: 2021-10-23 07:43:34             🧑  作者: Mango

给定一个矩阵mat[][] ,任务是检查矩阵的行主序路径是否是回文。

例子:

方法:思想是遍历半矩阵,同时检查其对半元素是否相同。那是对于 i 和 j 的索引,检查N - i - 1  M - i - 1  .如果任何索引存在不匹配,则打印 NO。

下面是上述方法的实现:

C++
// C++ implementation to check if
// row-major order traversal of
// matrix is palindrome or not
 
#include 
using namespace std;
 
// Function to check if row-major order
// traversal of the matrix is is palindrome
bool isPal(int a[3][3], int n, int m)
{
    // Loop to check if the matrix is
    // matrix is palindrome or not
    for (int i = 0; i < n / 2; i++) {
        for (int j = 0; j < m - 1; j++) {
            if (a[i][j] != a[n - 1 - i][m - 1 - j])
                return false;
        }
    }
    return true;
}
 
// Driver Code
int main()
{
    int n = 3, m = 3;
    int a[3][3] = { { 1, 2, 3 },
                    { 4, 5, 4 },
                    { 3, 2, 1 } };
    if (isPal(a, n, m)) {
        cout << "YES" << endl;
    }
    else {
        cout << "NO" << endl;
    }
}


Java
// Java implementation to check if
// row-major order traversal of
// matrix is palindrome or not
import java.util.*;
 
class GFG{
 
// Function to check if row-major order
// traversal of the matrix is is palindrome
static boolean isPal(int a[][], int n, int m)
{
     
    // Loop to check if the matrix is
    // matrix is palindrome or not
    for(int i = 0; i < n / 2; i++)
    {
       for(int j = 0; j < m - 1; j++)
       {
          if (a[i][j] != a[n - 1 - i][m - 1 - j])
              return false;
       }
    }
    return true;
}
 
// Driver Code
public static void main(String[] args)
{
    int n = 3, m = 3;
    int a[][] = { { 1, 2, 3 },
                  { 4, 5, 4 },
                  { 3, 2, 1 } };
                   
    if (isPal(a, n, m))
    {
        System.out.print("YES" + "\n");
    }
    else
    {
        System.out.print("NO" + "\n");
    }
}
}
 
// This code is contributed by gauravrajput1


Python3
# Python3 implementation to check if
# row-major order traversal of
# matrix is palindrome or not
 
# Function to check if row-major order
# traversal of the matrix is is palindrome
def isPal(a, n, m):
     
    # Loop to check if the matrix is
    # matrix is palindrome or not
    for i in range(0, n // 2):
        for j in range(0, m - 1):
            if (a[i][j] != a[n - 1 - i][m - 1 - j]):
                return False;
 
    return True;
 
# Driver Code
if __name__ == '__main__':
    n = 3;
    m = 3;
    a = [[1, 2, 3], [4, 5, 4], [3, 2, 1]];
 
    if (isPal(a, n, m)):
        print("YES");
    else:
        print("NO");
 
# This code is contributed by Princi Singh


C#
// C# implementation to check if
// row-major order traversal of
// matrix is palindrome or not
using System;
 
class GFG{
 
// Function to check if row-major order
// traversal of the matrix is is palindrome
static bool isPal(int[,]a, int n, int m)
{
     
    // Loop to check if the matrix is
    // matrix is palindrome or not
    for(int i = 0; i < n / 2; i++)
    {
       for(int j = 0; j < m - 1; j++)
       {
           if (a[i, j] != a[n - 1 - i,
                            m - 1 - j])
               return false;
       }
    }
    return true;
}
 
// Driver Code
public static void Main(String[] args)
{
    int n = 3, m = 3;
    int[,]a = { { 1, 2, 3 },
                { 4, 5, 4 },
                { 3, 2, 1 } };
                     
    if (isPal(a, n, m))
    {
        Console.Write("YES" + "\n");
    }
    else
    {
        Console.Write("NO" + "\n");
    }
}
}
 
// This code is contributed by gauravrajput1


Javascript


输出:
YES