Python - K 之后最小的缺失元素

给定一个List，获取List中K之后的最小缺失元素。

Input : test_list = [1, 3, 4, 5, 7, 9, 10], K = 5 
Output : 6 
Explanation : After 5, 6 is 1st element missing in list.

Input : test_list = [1, 3, 4, 5, 7, 9, 11], K = 9 
Output : 10 
Explanation : After 9, 10 is 1st element missing in list. 

方法：使用循环

在这里，我们遍历数字并使用条件检查列表中是否存在大于 K 的元素。

Python3

# Python3 code to demonstrate working of
# Smallest missing element after K
# Using loop
  
# initializing list
test_list = [1, 3, 4, 5, 7, 9, 10]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K
K = 7
  
ele = 1
  
# infinite loop to break at element found
while(1):
  
        # checking if greater than K and not in list
    if ele > K and ele not in test_list:
        res = ele
        break
    ele = ele + 1
  
# printing result
print("The Smallest element greater than K in list : " + str(res))

输出

The original list is : [1, 3, 4, 5, 7, 9, 10]
The Smallest element greater than K in list : 8