通过用长度替换除第一个和最后一个以外的所有字符来缩写给定的字符串

给定字符串str，任务是将给定字符串转换为其缩写形式：第一个字符，第一个和最后一个字符之间的字符数，以及字符串的最后一个字符。

例子：

Input: str = “internationalization”
Output: i18n
Explanation: First letter ‘i’, followed by number of letters between ‘i’ and ‘n’ i.e. 18, and the last letter ‘n’.

Input: str = “geeksforgeeks”
Output: g11s

方法：给定的问题是一个基于实现的问题，可以通过以下步骤解决：

• 打印给定字符串str[0]的第一个字符。
• 将字符串的长度存储在变量len中并打印len – 2 。
• 打印字符串的最后一个字符，即str[len -1] 。

下面是上述方法的实现：

C++

// C++ program of the above approach
#include 
using namespace std;
 
// Function to convert the given
// string into its abbreviation
void abbreviateWord(string str)
{
    // Stores the length of the string
    int len = str.size();
 
    // Print 1st character
    cout << str[0];
 
    // Print count of characters
    // in between
    cout << len - 2;
 
    // Print last character
    cout << str[len - 1];
}
 
// Driver Code
int main()
{
    string str = "internationalization";
    abbreviateWord(str);
 
    return 0;
}

Java

// Java program for the above approach
import java.util.*;
public class GFG
{
   
  // Function to convert the given
  // string into its abbreviation
  static void abbreviateWord(String str)
  {
 
    // Stores the length of the string
    int len = str.length();
 
    // Print 1st character
    System.out.print(str.charAt(0));
 
    // Print count of characters
    // in between
    System.out.print(len - 2);
 
    // Print last character
    System.out.print(str.charAt(len - 1));
  }
 
  // Driver Code
  public static void main(String args[])
  {
    String str = "internationalization";
    abbreviateWord(str);
 
  }
}
 
// This code is contributed by Samim Hossain Mondal.

Python3

# Python code for the above approach
 
# Function to convert the given
# string into its abbreviation
def abbreviateWord(str):
 
    # Stores the length of the string
    _len = len(str);
 
    # Print 1st character
    print(str[0], end="");
 
    # Print count of characters
    # in between
    print(_len - 2, end="");
 
    # Print last character
    print(str[_len - 1], end="");
 
 
# Driver Code
str = "internationalization";
abbreviateWord(str);
 
# This code is contributed gfgking

C#

// C# program of the above approach
using System;
class GFG
{
   
// Function to convert the given
// string into its abbreviation
static void abbreviateWord(string str)
{
   
    // Stores the length of the string
    int len = str.Length;
 
    // Print 1st character
    Console.Write(str[0]);
 
    // Print count of characters
    // in between
    Console.Write(len - 2);
 
    // Print last character
    Console.Write(str[len - 1]);
}
 
// Driver Code
public static void Main()
{
    string str = "internationalization";
    abbreviateWord(str);
 
}
}
 
// This code is contributed by Samim Hossain Mondal.

Javascript

      // JavaScript code for the above approach
 
      // Function to convert the given
      // string into its abbreviation
      function abbreviateWord(str)
      {
       
          // Stores the length of the string
          let len = str.length;
 
          // Print 1st character
          document.write(str[0]);
 
          // Print count of characters
          // in between
          document.write(len - 2);
 
          // Print last character
          document.write(str[len - 1]);
      }
 
      // Driver Code
      let str = "internationalization";
      abbreviateWord(str);
 
// This code is contributed by Potta Lokesh
  

输出

i18n

时间复杂度： O(1)
辅助空间： O(1)