📜  最长非回文子串

📅  最后修改于: 2022-05-13 01:57:08.083000             🧑  作者: Mango

最长非回文子串

给定一个大小为 n 的字符串。任务是找到不是回文的最大子串的长度。
例子:

Input : abba 
Output : 3
Here maximum length non-palindromic substring is
'abb' which is of length '3'. There could be other
non-palindromic sub-strings also of length three 
like 'bba' in this case.

Input : a
Output : 0

一个简单的解决方案是考虑每个子字符串并检查它是否是回文。最后返回最长的非回文子串的长度。
一个有效的解决方案基于以下方法。

Check for the case where all characters of
the string are same or not.
    If yes, then answer will be '0'.
Else check whether the given string of size 
'n' is palindrome or not. 
    If yes, then answer will be 'n-1'
Else answer will be 'n' 

C++
// C++ implementation to find maximum length
// substring which is not palindrome
#include 
using namespace std;
 
// utility function to check whether
// a string is palindrome or not
bool isPalindrome(string str)
{
    // Check for palindrome.
    int n = str.size();
    for (int i=0; i < n/2; i++)
        if (str.at(i) != str.at(n-i-1))
            return false;
 
    // palindrome string
    return true;
}
 
// function to find maximum length
// substring which is not palindrome
int maxLengthNonPalinSubstring(string str)
{
    int n = str.size();
    char ch = str.at(0);
 
    // to check whether all characters
    // of the string are same or not
    int i = 1;
    for (i=1; iJava
//Java implementation to find maximum length
//substring which is not palindrome
public class GFG
{
    // utility function to check whether
    // a string is palindrome or not
    static Boolean isPalindrome(String str)
    {
        int n = str.length();
 
        // Check for palindrome.
        for (int i = 0; i < n/2; i++)
            if (str.charAt(i) != str.charAt(n-i-1))
                return false;
 
        // palindrome string
        return true;
    }
 
    // function to find maximum length
    // substring which is not palindrome
    static int maxLengthNonPalinSubstring(String str)
    {
        int n = str.length();
        char ch = str.charAt(0);
 
        // to check whether all characters
        // of the string are same or not
        int i = 1;
        for (i = 1; i < n; i++)
            if(str.charAt(i) != ch)
                break;
 
        // All characters are same, we can't
        // make a non-palindromic string.
        if (i == n)
            return 0;
 
        // If string is palindrome, we can make
        // it non-palindrome by removing any
        // corner character
        if (isPalindrome(str))
            return n-1;
 
        // Complete string is not a palindrome.
        return n;
    }
 
    // Driver Program to test above function
    public static void main(String args[])
    {
        String str = "abba";
        System.out.println("Maximum Length = "
             + maxLengthNonPalinSubstring(str));
    }
}
// This code is contributed by Sumit Ghosh


Python 3
# Python 3 implementation to find maximum
# length substring which is not palindrome
 
# utility function to check whether
# a string is palindrome or not
def isPalindrome(str):
     
    # Check for palindrome.
    n = len(str)
    for i in range(n // 2):
        if (str[i] != str[n - i - 1]):
            return False
 
    # palindrome string
    return True
 
# function to find maximum length
# substring which is not palindrome
def maxLengthNonPalinSubstring(str):
    n = len(str)
    ch = str[0]
 
    # to check whether all characters
    # of the string are same or not
    i = 1
    for i in range(1, n):
        if (str[i] != ch):
            break
 
    # All characters are same, we can't
    # make a non-palindromic string.
    if (i == n):
        return 0
 
    # If string is palindrome, we can make
    # it non-palindrome by removing any
    # corner character
    if (isPalindrome(str)):
        return n - 1
 
    # Complete string is not a palindrome.
    return n
 
# Driver Code
if __name__ == "__main__":
     
    str = "abba"
    print("Maximum length =",
           maxLengthNonPalinSubstring(str))
 
# This code is contributed by ita_c


C#
// C# implementation to find maximum length
// substring which is not palindrome
using System;
 
class GFG {
     
    // utility function to check whether
    // a string is palindrome or not
    static bool isPalindrome(String str)
    {
        int n = str.Length;
 
        // Check for palindrome.
        for (int i = 0; i < n / 2; i++)
            if (str[i] != str[n - i - 1])
                return false;
 
        // palindrome string
        return true;
    }
 
    // function to find maximum length
    // substring which is not palindrome
    static int maxLengthNonPalinSubstring(String str)
    {
        int n = str.Length;
        char ch = str[0];
 
        // to check whether all characters
        // of the string are same or not
        int i = 1;
        for (i = 1; i < n; i++)
            if(str[i] != ch)
                break;
 
        // All characters are same, we can't
        // make a non-palindromic string.
        if (i == n)
            return 0;
 
        // If string is palindrome, we can
        // make it non-palindrome by removing
        // any corner character
        if (isPalindrome(str))
            return n-1;
 
        // Complete string is not a palindrome.
        return n;
    }
 
    // Driver code
    public static void Main()
    {
        String str = "abba";
        Console.Write("Maximum Length = "
                      + maxLengthNonPalinSubstring(str));
    }
}
 
// This code is contributed by nitin mittal


PHP


Javascript


输出:

Maximum length = 3