Python - 用字典映射矩阵

给定一个矩阵，用字典值映射它的值。

Input : test_list = [[4, 2, 1], [1, 2, 3]], sub_dict = {1 : “gfg”, 2: “best”, 3 : “CS”, 4 : “Geeks”}
Output : [[‘Geeks’, ‘best’, ‘gfg’], [‘gfg’, ‘best’, ‘CS’]]
Explanation : Matrix elements are substituted using dictionary.

Input : test_list = [[4, 2, 1]], sub_dict = {1 : “gfg”, 2: “best”, 4 : “Geeks”}
Output : [[‘Geeks’, ‘best’, ‘gfg’]]
Explanation : Matrix elements are substituted using dictionary.

方法#1：使用循环

这是执行此任务的蛮力方式。在这里，我们迭代 Matrix 的所有元素并从字典中映射。

Python3

# Python3 code to demonstrate working of 
# Mapping Matrix with Dictionary
# Using loop
  
# initializing list
test_list = [[4, 2, 1], [1, 2, 3], [4, 3, 1]]
  
# printing original list
print("The original list : " + str(test_list))
  
# initializing dictionary
sub_dict = {1 : "gfg", 2: "best", 3 : "CS", 4 : "Geeks"}
  
# Using loop to perform required mapping
res = []
for sub in test_list:
    temp = []
    for ele in sub:
          
        # mapping values from dictionary
        temp.append(sub_dict[ele])
    res.append(temp)
  
# printing result 
print("Converted Mapped Matrix : " + str(res))

输出

The original list : [[4, 2, 1], [1, 2, 3], [4, 3, 1]]
Converted Mapped Matrix : [['Geeks', 'best', 'gfg'], ['gfg', 'best', 'CS'], ['Geeks', 'CS', 'gfg']]

方法#2：使用列表理解

这是可以执行此任务的另一种方式。这只是上述方法的简写。

蟒蛇3

# Python3 code to demonstrate working of 
# Mapping Matrix with Dictionary
# Using list comprehension
  
# initializing list
test_list = [[4, 2, 1], [1, 2, 3], [4, 3, 1]]
  
# printing original list
print("The original list : " + str(test_list))
  
# initializing dictionary
sub_dict = {1 : "gfg", 2: "best", 3 : "CS", 4 : "Geeks"}
  
# Using list comprehension to perform required mapping
# in one line 
res = [[sub_dict[val] for val in sub] for sub in test_list]
  
# printing result 
print("Converted Mapped Matrix : " + str(res))

输出

The original list : [[4, 2, 1], [1, 2, 3], [4, 3, 1]]
Converted Mapped Matrix : [['Geeks', 'best', 'gfg'], ['gfg', 'best', 'CS'], ['Geeks', 'CS', 'gfg']]