通过添加给定字符串的所有字符找到字符

给定一个由小写英文字母组成的字符串str 。任务是将所有字符值相加，即'a' = 1，'b' = 2，'c' = 3，...，'z' = 26 ，并输出与总和值对应的字符。如果超过 26，则取 sum % 26。
例子：

Input: str = “gfg”
Output: t
(g + f + g) = 7 + 6 + 7 = 20 and t = 20
Input: str = “geeks”
Output: u

编程需要懂一点英语

方法：

找到字符串所有字符的总和并将其存储在变量sum中。
如果sum % 26 = 0则打印'z' 。
否则更新sum = sum % 26并打印(sum + 'a' + 1) 。

下面是上述方法的实现：

C++

// C++ implementation of the approach
#include 
using namespace std;
 
// Function to return the required character
char getChar(string str)
{
 
    // To store the sum of the characters
    // of the given string
    int sum = 0;
 
    for (int i = 0; i < str.length(); i++) {
 
        // Add the current character to the sum
        sum += (str[i] - 'a' + 1);
    }
 
    // Return the required character
    if (sum % 26 == 0)
        return 'z';
    else {
        sum = sum % 26;
        return (char)('a' + sum - 1);
    }
}
 
// Driver code
int main()
{
    string str = "gfg";
 
    cout << getChar(str);
 
    return 0;
}

Java

// Java implementation of the approach
class GFG
{
     
// Function to return the required character
static char getChar(String str)
{
 
    // To store the sum of the characters
    // of the given string
    int sum = 0;
 
    for (int i = 0; i < str.length(); i++)
    {
 
        // Add the current character to the sum
        sum += (str.charAt(i) - 'a' + 1);
    }
 
    // Return the required character
    if (sum % 26 == 0)
        return 'z';
    else
    {
        sum = sum % 26;
        return (char)('a' + sum - 1);
    }
}
 
// Driver code
public static void main (String[] args)
{
    String str = "gfg";
 
    System.out.println(getChar(str));
}
}
 
// This code is contributed by AnkitRai01

Python3

# Python3 implementation of the approach
 
# Function to return the required character
def getChar(strr):
 
    # To store the summ of the characters
    # of the given string
    summ = 0
 
    for i in range(len(strr)):
 
        # Add the current character to the summ
        summ += (ord(strr[i]) - ord('a') + 1)
 
    # Return the required character
    if (summ % 26 == 0):
        return ord('z')
    else:
        summ = summ % 26
        return chr(ord('a') + summ - 1)
 
# Driver code
strr = "gfg"
 
print(getChar(strr))
 
# This code is contributed by Mohit Kumar

C#

// C# implementation of the approach
using System;
 
class GFG
{
     
// Function to return the required character
static char getChar(String str)
{
 
    // To store the sum of the characters
    // of the given string
    int sum = 0;
 
    for (int i = 0; i < str.Length; i++)
    {
 
        // Add the current character to the sum
        sum += (str[i] - 'a' + 1);
    }
 
    // Return the required character
    if (sum % 26 == 0)
        return 'z';
    else
    {
        sum = sum % 26;
        return (char)('a' + sum - 1);
    }
}
 
// Driver code
public static void Main (String[] args)
{
    String str = "gfg";
 
    Console.WriteLine(getChar(str));
}
}
     
// This code is contributed by PrinciRaj1992

Javascript

输出：