用标点符号对字符串进行排序的Python程序

给定字符串列表，按标点符号数排序。

Input : test_list = [“gfg@%^”, “is”, “Best!”] 
Output : [‘is’, ‘Best!’, ‘gfg@%^’] 
Explanation : 0 < 1 < 3, sorted by punctuation count.

Input : test_list = [“gfg@%^”, “Best!”] 
Output : [ ‘Best!’, ‘gfg@%^’] 
Explanation : 1 < 3, sorted by punctuation count. 

方法 #1：使用字符串.punctuation + sort()

在这种情况下，排序是使用 sort() 完成的，标点符号是从字符串库的标点符号池中提取的。执行就地排序。

Python3

# Python3 code to demonstrate working of
# Sort Strings by Punctuation count
# Using string.punctuation + sort()
from string import punctuation
 
def get_pnc_count(string):
     
    # getting punctuation count
    return len([ele for ele in string if ele in punctuation])
 
# initializing list
test_list = ["gfg@%^", "is", "Best!", "fo@#r", "@#$ge24eks!"]
 
# printing original list
print("The original list is : " + str(test_list))
 
# performing inplace sort
test_list.sort(key = get_pnc_count)
 
# printing result
print("Sorted Strings list : " + str(test_list))

输出：

The original list is : [‘gfg@%^’, ‘is’, ‘Best!’, ‘fo@#r’, ‘@#$ge24eks!’] 
Sorted Strings list : [‘is’, ‘Best!’, ‘fo@#r’, ‘gfg@%^’, ‘@#$ge24eks!’] 
 

方法 #2：使用sorted() + 标点符号 + lambda

在此，我们使用 lambda 使用 sorted() 执行排序，以避免外部函数执行过滤使用标点提取的标点的任务。

蟒蛇3

# Python3 code to demonstrate working of
# Sort Strings by Punctuation count
# Using sorted() + punctuation + lambda
from string import punctuation
 
# initializing list
test_list = ["gfg@%^", "is", "Best!", "fo@#r", "@#$ge24eks!"]
 
# printing original list
print("The original list is : " + str(test_list))
 
# performing sort using sorted() with lambda
# function for filtering
res = sorted(test_list, key=lambda string: len(
    [ele for ele in string if ele in punctuation]))
 
# printing result
print("Sorted Strings list : " + str(res))

输出：

The original list is : [‘gfg@%^’, ‘is’, ‘Best!’, ‘fo@#r’, ‘@#$ge24eks!’] 
Sorted Strings list : [‘is’, ‘Best!’, ‘fo@#r’, ‘gfg@%^’, ‘@#$ge24eks!’]