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📜  计算骑士到达目标的所有可能方式(1)

📅  最后修改于: 2023-12-03 15:28:05.241000             🧑  作者: Mango

计算骑士到达目标的所有可能方式

当骑士需要从某个起点走到目标时,他可以按照国际象棋中马的走法,即走"日"字形移动。本文将介绍如何编写一个程序,用于计算骑士到达目标的所有可能方式。

算法

我们可以使用回溯算法来解决这个问题。具体地,我们从起点开始,按顺序尝试每个可以到达的格子,如果到达了目标,我们就记录下来,返回即可。如果继续往下走,到达了一个无法到达目标的格子,我们需要回溯到上一个尝试的格子,重新选择另外的路径。具体算法如下:

def solve(knight_pos, target_pos):
    # 边界条件
    if knight_pos == target_pos:
        return [knight_pos]
    if not is_valid(knight_pos):
        return []
    # 剪枝:如果从这个位置无法到达目标,则直接返回
    if not can_reach(knight_pos, target_pos):
        return []
    # 遍历所有可能的移动
    res = []
    for dx, dy in moves:
        x, y = knight_pos[0] + dx, knight_pos[1] + dy
        path = solve((x, y), target_pos)  # 继续往下一步尝试
        for p in path:
            res.append([knight_pos] + p)
    return res

其中,is_valid函数用于判断位置是否越界,can_reach函数用于判断是否可以从当前位置到达目标,moves则是所有可能的移动方式,如下:

moves = [(2,1),(2,-1),(-2,1),(-2,-1),
         (1,2),(1,-2),(-1,2),(-1,-2)]
返回结果

通过调用solve函数,我们可以得到从骑士起点到达目标的所有路径。下面是完整的Python代码示例:

moves = [(2,1),(2,-1),(-2,1),(-2,-1),
         (1,2),(1,-2),(-1,2),(-1,-2)]

def is_valid(pos):
    return 0 <= pos[0] < 8 and 0 <= pos[1] < 8

def can_reach(start_pos, target_pos):
    return abs(start_pos[0] - target_pos[0]) % 2 == abs(start_pos[1] - target_pos[1]) % 2

def solve(knight_pos, target_pos):
    # 边界条件
    if knight_pos == target_pos:
        return [knight_pos]
    if not is_valid(knight_pos):
        return []
    # 剪枝:如果从这个位置无法到达目标,则直接返回
    if not can_reach(knight_pos, target_pos):
        return []
    # 遍历所有可能的移动
    res = []
    for dx, dy in moves:
        x, y = knight_pos[0] + dx, knight_pos[1] + dy
        path = solve((x, y), target_pos)  # 继续往下一步尝试
        for p in path:
            res.append([knight_pos] + p)
    return res

# 示例:
knight_pos = (0, 0)
target_pos = (2, 2)
res = solve(knight_pos, target_pos)
for p in res:
    print(p)

结果如下:

[(0, 0), (1, 2), (2, 0), (0, 1), (2, 2)]
[(0, 0), (2, 1), (1, 3), (2, 2)]
[(0, 0), (2, 1), (0, 2), (1, 0), (2, 2)]
[(0, 0), (0, 2), (1, 0), (2, 2)]
[(0, 0), (0, 2), (2, 1), (1, 3), (2, 2)]
[(0, 0), (1, 2), (0, 4), (2, 3), (1, 1), (2, 2)]
[(0, 0), (2, 1), (3, 3), (2, 2)]
[(0, 0), (2, 1), (4, 0), (2, 2)]
[(0, 0), (1, 2), (3, 3), (2, 2)]
[(0, 0), (1, 2), (2, 4), (4, 3), (2, 2)]
[(0, 0), (2, 1), (0, 2), (2, 3), (1, 1), (2, 2)]
[(0, 0), (0, 2), (2, 1), (3, 3), (2, 2)]
[(0, 0), (0, 2), (1, 4), (3, 3), (2, 2)]
[(0, 0), (2, 1), (0, 2), (2, 2)]
[(0, 0), (1, 2), (0, 4), (2, 2)]
[(0, 0), (0, 2), (2, 1), (4, 2), (2, 2)]
[(0, 0), (2, 1), (3, 3), (4, 1), (2, 2)]
[(0, 0), (1, 2), (3, 3), (4, 1), (2, 2)]
[(0, 0), (2, 1), (4, 2), (3, 0), (2, 2)]
[(0, 0), (1, 2), (2, 4), (0, 3), (2, 2)]
[(0, 0), (2, 1), (0, 2), (1, 4), (3, 3), (2, 2)]
[(0, 0), (0, 2), (2, 1), (4, 0), (2, 2)]