顾名思义,前哨线性搜索是一种线性搜索,与传统的线性搜索相比,它的比较次数有所减少。当对大小为N的数组执行线性搜索时,在最坏的情况下,当将要搜索的元素与数组的所有元素进行比较时,总共进行N次比较,并且对(N + 1)个进行比较要比较的元素的索引,以使索引不超出数组的范围,可以在Sentinel线性搜索中减少该范围。
在此搜索中,将数组的最后一个元素替换为要搜索的元素,然后对数组执行线性搜索,而无需检查当前索引是否在数组的索引范围内,因为要搜索的元素即使自从最后一个元素替换为原始数组以来,即使在原始数组中不存在该数组,也肯定会在数组内部找到它。因此,要检查的索引永远不会超出数组的范围。最坏情况下的比较次数为(N + 2)。
例子:
Input: arr[] = {10, 20, 180, 30, 60, 50, 110, 100, 70}, x = 180
Output: 180 is present at index 2
Input: arr[] = {10, 20, 180, 30, 60, 50, 110, 100, 70}, x = 90
Output: Not found
下面是上述方法的实现:
C++
// C++ implementation of the approach
#include
using namespace std;
// Function to search x in the given array
void sentinelSearch(int arr[], int n, int key)
{
// Last element of the array
int last = arr[n - 1];
// Element to be searched is
// placed at the last index
arr[n - 1] = key;
int i = 0;
while (arr[i] != key)
i++;
// Put the last element back
arr[n - 1] = last;
if ((i < n - 1) || (arr[n - 1] == key))
cout << key << " is present at index " << i;
else
cout << "Element Not found";
}
// Driver code
int main()
{
int arr[] = { 10, 20, 180, 30, 60, 50, 110, 100, 70 };
int n = sizeof(arr) / sizeof(arr[0]);
int key = 180;
sentinelSearch(arr, n, key);
return 0;
}
// This code is contributed by Mandeep Dalavi
Java
// Java implementation of the approach
class GFG {
// Function to search x in the given array
static void sentinelSearch(int arr[], int n, int key)
{
// Last element of the array
int last = arr[n - 1];
// Element to be searched is
// placed at the last index
arr[n - 1] = key;
int i = 0;
while (arr[i] != key)
i++;
// Put the last element back
arr[n - 1] = last;
if ((i < n - 1) || (arr[n - 1] == key))
System.out.println(key + " is present at index "
+ i);
else
System.out.println("Element Not found");
}
// Driver code
public static void main(String[] args)
{
int arr[]
= { 10, 20, 180, 30, 60, 50, 110, 100, 70 };
int n = arr.length;
int key = 180;
sentinelSearch(arr, n, key);
}
}
// This code is contributed by Ankit Rai, Mandeep Dalavi
Python3
# Python3 implementation of the approach
# Function to search key in the given array
def sentinelSearch(arr, n, key):
# Last element of the array
last = arr[n - 1]
# Element to be searched is
# placed at the last index
arr[n - 1] = key
i = 0
while (arr[i] != key):
i += 1
# Put the last element back
arr[n - 1] = last
if ((i < n - 1) or (arr[n - 1] == key)):
print(key, "is present at index", i)
else:
print("Element Not found")
# Driver code
arr = [10, 20, 180, 30, 60, 50, 110, 100, 70]
n = len(arr)
key = 180
sentinelSearch(arr, n, key)
# This code is contributed by divyamohan123, Mandeep Dalavi
C#
// C# implementation of the approach
using System;
class GFG {
// Function to search x in the given array
static void sentinelSearch(int[] arr, int n, int key)
{
// Last element of the array
int last = arr[n - 1];
// Element to be searched is
// placed at the last index
arr[n - 1] = key;
int i = 0;
while (arr[i] != key)
i++;
// Put the last element back
arr[n - 1] = last;
if ((i < n - 1) || (arr[n - 1] == key))
Console.WriteLine(key + " is present"
+ " at index " + i);
else
Console.WriteLine("Element Not found");
}
// Driver code
public static void Main()
{
int[] arr
= { 10, 20, 180, 30, 60, 50, 110, 100, 70 };
int n = arr.Length;
int key = 180;
sentinelSearch(arr, n, key);
}
}
// This code is contributed by Mohit kumar, Mandeep Dalavi
输出:
180 is present at index 2