查找除以N但严格小于N的最大复合数

给定一个合成数N ，任务是找到除以N并严格小于N的最大合成数。如果没有这样的数字，则打印-1。

例子：

Input: N = 16
Output: 8
Explanation:
All numbers that divide 16 are { 1, 2, 4, 8, 16 }
out of which 8 is largest composite number(lesser than 16) that divides 16.

Input: N = 100
Output: -1

方法：
由于N是一个复合数字，因此N可以是两个数字的乘积，使得一个是质数，另一个是一个复合数字，如果我们找不到N的对，那么最大的复合数字会小于N N的除法不存在。
要找到最大的合成数，请找到除以N的最小素数(例如a)。然后，除以N且小于N的最大复合数可以由(N / a)给出。

步骤如下：

1. 找出N的最小素数(例如a)。
2. 检查(N / a)是否为质数。如果是，那么我们找不到最大的复合数。
3. 其他(N / a)是除N且小于N的最大复合数。

下面是上述方法的实现：

C++

// C++ program to find the largest
// composite number that divides
// N which is less than N
#include 
using namespace std;
  
// Function to check whether
// a number is prime or not
bool isPrime(int n)
{
    // Corner case
    if (n <= 1)
        return false;
  
    // Check from 2 to n-1
    for (int i = 2; i < n; i++)
        if (n % i == 0)
            return false;
  
    return true;
}
  
// Function that find the largest
// composite number which divides
// N and less than N
int getSmallestPrimefactor(int n)
{
    // Find the prime number
    for (int i = 2; i <= sqrt(n); i++) {
        if (n % i == 0)
            return i;
    }
}
  
// Driver's Code
int main()
{
    int N = 100;
    int a;
  
    // Get the smallest prime
    // factor
    a = getSmallestPrimefactor(N);
  
    // Check if (N/a) is prime
    // or not
    // If Yes print "-1"
    if (isPrime(N / a)) {
        cout << "-1";
    }
  
    // Else print largest composite
    // number (N/a)
    else {
        cout << N / a;
    }
    return 0;
}

Java

// Java program to find the largest
// composite number that divides
// N which is less than N
import java.util.*;
  
class GFG{
  
// Function to check whether
// a number is prime or not
static boolean isPrime(int n)
{
      
    // Corner case
    if (n <= 1)
        return false;
  
    // Check from 2 to n-1
    for(int i = 2; i < n; i++)
    {
       if (n % i == 0)
           return false;
    }
    return true;
}
  
// Function that find the largest
// composite number which divides
// N and less than N
static int getSmallestPrimefactor(int n)
{
      
    // Find the prime number
    for(int i = 2; i <= Math.sqrt(n); i++)
    {
       if (n % i == 0)
           return i;
    }
    return -1;
}
  
// Driver Code
public static void main(String[] args)
{
    int N = 100;
    int a;
  
    // Get the smallest prime
    // factor
    a = getSmallestPrimefactor(N);
  
    // Check if (N/a) is prime or 
    // not. If Yes print "-1" 
    if (isPrime(N / a)) 
    {
        System.out.print("-1");
    }
  
    // Else print largest composite
    // number (N/a)
    else 
    {
        System.out.print(N / a);
    }
}
}
  
// This code is contributed by amal kumar choubey

Python3

# Python3 program to find the largest 
# composite number that divides 
# N which is less than N 
import math
  
# Function to check whether 
# a number is prime or not
def isPrime(n):
  
    # Corner case 
    if (n <= 1): 
        return False; 
  
    # Check from 2 to n-1 
    for i in range(2, n):
        if (n % i == 0):
            return False; 
  
    return True; 
  
# Function that find the largest 
# composite number which divides 
# N and less than N 
def getSmallestPrimefactor(n):
      
    # Find the prime number 
    for i in range(2, (int)(math.sqrt(n) + 1)):
        if (n % i == 0):
            return i; 
  
    return -1
  
# Driver Code 
N = 100; 
  
# Get the smallest prime 
# factor 
a = getSmallestPrimefactor(N); 
  
# Check if (N/a) is prime 
# or not. If Yes print "-1" 
if ((isPrime((int)(N / a)))):
    print(-1) 
      
# Else print largest composite 
# number (N/a) 
else:
    print((int)(N / a)); 
  
# This code is contributed by grand_master

C#

// C# program to find the largest
// composite number that divides
// N which is less than N
using System;
class GFG{
  
// Function to check whether
// a number is prime or not
static bool isPrime(int n)
{
      
    // Corner case
    if (n <= 1)
        return false;
  
    // Check from 2 to n-1
    for(int i = 2; i < n; i++)
    {
        if (n % i == 0)
            return false;
    }
    return true;
}
  
// Function that find the largest
// composite number which divides
// N and less than N
static int getSmallestPrimefactor(int n)
{
      
    // Find the prime number
    for(int i = 2; i <= Math.Sqrt(n); i++)
    {
        if (n % i == 0)
            return i;
    }
    return -1;
}
  
// Driver Code
public static void Main()
{
    int N = 100;
    int a;
  
    // Get the smallest prime
    // factor
    a = getSmallestPrimefactor(N);
  
    // Check if (N/a) is prime or 
    // not. If Yes print "-1" 
    if (isPrime(N / a)) 
    {
        Console.Write("-1");
    }
  
    // Else print largest composite
    // number (N/a)
    else
    {
        Console.Write(N / a);
    }
}
}
  
// This code is contributed by Code_Mech

输出：

50

时间复杂度： O(sqrt(N))