Python全组合字典列表

给定 2 个列表，形成所有可能的字典组合，这些组合可以通过从 list1 中获取键和从 list2 中获取值来形成。

Input : test_list1 = [“Gfg”, “is”, “Best”], test_list2 = [4] 
Output : [{‘Gfg’: 4, ‘is’: 4, ‘Best’: 4}]
Explanation : All combinations dictionary list extracted.
 

Input : test_list1 = [“Gfg”, “is”, “Best”], test_list2 = [5, 6] 
Output : [{‘Gfg’: 5, ‘is’: 5, ‘Best’: 5}, {‘Gfg’: 5, ‘is’: 5, ‘Best’: 6}, {‘Gfg’: 5, ‘is’: 6, ‘Best’: 5}, {‘Gfg’: 5, ‘is’: 6, ‘Best’: 6}, {‘Gfg’: 6, ‘is’: 5, ‘Best’: 5}, {‘Gfg’: 6, ‘is’: 5, ‘Best’: 6}, {‘Gfg’: 6, ‘is’: 6, ‘Best’: 5}, {‘Gfg’: 6, ‘is’: 6, ‘Best’: 6}] 
Explanation : All combinations dictionary list extracted. 
 

方法 #1：使用 product() + 字典推导 + 列表推导

在这里，我们使用 product() 获得所有可能的组合，并且字典理解生成每个字典，列表理解用于迭代生成的组合。

Python3

# Python3 code to demonstrate working of 
# All combination Dictionary List
# Using product() + list comprehension + dictionary comprehension
from itertools import product
  
# initializing lists
test_list1 = ["Gfg", "is", "Best"]
test_list2 = [4, 5]
  
# printing original lists
print("The original list 1 is : " + str(test_list1))
print("The original list 2 is : " + str(test_list2))
  
# generating combinations
temp = product(test_list2, repeat = len(test_list1))
  
# constructing dicts using combinations
res = [{key : val for (key , val) in zip(test_list1, ele)} for ele in temp]
  
# printing result 
print("The combinations dictionary : " + str(res))

输出：

The original list 1 is : [‘Gfg’, ‘is’, ‘Best’]
The original list 2 is : [4, 5]
The combinations dictionary : [{‘Gfg’: 4, ‘is’: 4, ‘Best’: 4}, {‘Gfg’: 4, ‘is’: 4, ‘Best’: 5}, {‘Gfg’: 4, ‘is’: 5, ‘Best’: 4}, {‘Gfg’: 4, ‘is’: 5, ‘Best’: 5}, {‘Gfg’: 5, ‘is’: 4, ‘Best’: 4}, {‘Gfg’: 5, ‘is’: 4, ‘Best’: 5}, {‘Gfg’: 5, ‘is’: 5, ‘Best’: 4}, {‘Gfg’: 5, ‘is’: 5, ‘Best’: 5}]

方法 #2：使用 permutations() + 字典推导 + 列表推导 [对于唯一元素]

如果我们要求值都是唯一的，可以使用 permutations() 代替 product() 来完成此任务。

蟒蛇3

# Python3 code to demonstrate working of
# All combination Dictionary List
# Using product() + list comprehension + dictionary comprehension
from itertools import permutations
  
# initializing lists
test_list1 = ["Gfg", "is", "Best"]
test_list2 = [4, 5, 6]
  
# printing original lists
print("The original list 1 is : " + str(test_list1))
print("The original list 2 is : " + str(test_list2))
  
# generating combinations
temp = list(permutations(test_list2, len(test_list1)))
  
# constructing dicts using combinations
res = [{key: val for (key, val) in zip(test_list1, ele)} for ele in temp]
  
# printing result
print("The combinations dictionary : " + str(res))

输出：

The original list 1 is : [‘Gfg’, ‘is’, ‘Best’]
The original list 2 is : [4, 5, 6]
The combinations dictionary : [{‘Gfg’: 4, ‘is’: 5, ‘Best’: 6}, {‘Gfg’: 4, ‘is’: 6, ‘Best’: 5}, {‘Gfg’: 5, ‘is’: 4, ‘Best’: 6}, {‘Gfg’: 5, ‘is’: 6, ‘Best’: 4}, {‘Gfg’: 6, ‘is’: 4, ‘Best’: 5}, {‘Gfg’: 6, ‘is’: 5, ‘Best’: 4}]