C程序打印金字塔图案

给定一个正整数 n。任务是按照以下示例中的说明打印金字塔图案。
例子：

算法：

//Print All Pattern
printPattern(int N)
    // Print upper pattern
    /* 1
       22
       333
       ...
       N...(N)times   */
    for i->1 to N
        for j->1 to i
            print i
        print next line

    // Print lower triangle
    /* N-1....(N-1)times
       ...
       333
       22
       1 */
    for i->N-1 to 0
        for j->i to 0
            print i
        print next line

C++

// C++ program to print the pyramid pattern
#include 
using namespace std;
 
// Print the pattern upto n
void printPattern(int n)
{
    // Printing upper part
    for (int i = 1; i <= n; i++)
    {
        for (int j = 1; j <= i; j++)
            cout << i;       
        cout << "\n";
    }
 
    // printing lower part
    for (int i = n - 1; i > 0; i--)
    {
       for (int j = i; j > 0; j--)
            cout << i;       
        cout << "\n";
    }
}
 
// Driver Code
int main()
{
    int n = 8;
    printPattern(n);
    return 0;
}

Java

// Java program to print the pyramid pattern
 
class GFG {
     
// Print the pattern upto n
static void printPattern(int n)
{
    // Printing upper part
    for (int i = 1; i <= n; i++) {
    for (int j = 1; j <= i; j++)
        System.out.print(i);
    System.out.print("\n");
    }
 
    // printing lower part
    for (int i = n - 1; i > 0; i--) {
    for (int j = i; j > 0; j--)
        System.out.print(i);
    System.out.print("\n");
    }
}
 
// Driver code
public static void main(String arg[])
{
    int n = 8;
    printPattern(n);
}
}
 
// This code is contributed by Anant Agarwal.

Python3

# Python program to print
# the pyramid pattern
 
# Print the pattern upto n
def printPattern(n):
 
    # Printing upper part
    for i in range(n+1):
     
        for j in range(1,i+1):
            print(i,end="")       
        print("")
     
    # printing lower part
    for i in range(n - 1,0,-1):
     
        for j in range(i,0,-1):
            print(i,end="")       
        print("")
 
# driver code
n = 8
printPattern(n)
 
# This code is contributed
# by Anant Agarwal.
C#]  0; $i--) 
    {
    for ($j = $i; $j > 0; $j--) 
            echo $i;     
        echo "\n";
    }
}

    // Driver Code
    $n = 8;
    printPattern($n);

// This code is contributed by mits    
?>

JavaScript

输出：