Python - 从列表中删除每个元素都为 None 的元组

给定一个元组列表，删除所有值为 None 的元组。

Input : test_list = [(None, 2), (None, None), (3, 4), (12, 3), (None, )] 
Output : [(None, 2), (3, 4), (12, 3)] 
Explanation : All None tuples are removed.

Input : test_list = [(None, None), (None, None), (3, 4), (12, 3), (None, )] 
Output : [(3, 4), (12, 3)] 
Explanation : All None tuples are removed. 
 

方法 #1：使用all() +列表推导式

在这里，我们使用 all() 来检查所有 None 值是否被丢弃，列表理解会执行迭代任务。

Python3

# Python3 code to demonstrate working of 
# Remove None Tuples from List
# Using all() + list comprehension
  
# initializing list
test_list = [(None, 2), (None, None), (3, 4), (12, 3), (None, )]
  
# printing original list
print("The original list is : " + str(test_list))
  
# negating result for discarding all None Tuples
res = [sub for sub in test_list if not all(ele == None for ele in sub)]
  
# printing result 
print("Removed None Tuples : " + str(res))

输出：

The original list is : [(None, 2), (None, None), (3, 4), (12, 3), (None,)]
Removed None Tuples : [(None, 2), (3, 4), (12, 3)]

方法 #2：使用filter() + lambda + all()

在此方法中，过滤 None 元组的任务是使用 filter() 和 lambda函数完成的，以使用 all() 提供 None 检查功能。

蟒蛇3

# Python3 code to demonstrate working of 
# Remove None Tuples from List
# Using filter() + lambda + all()
  
# initializing list
test_list = [(None, 2), (None, None), (3, 4), (12, 3), (None, )]
  
# printing original list
print("The original list is : " + str(test_list))
  
# filter() + lambda to drive logic of discarding tuples
res = list(filter(lambda sub : not all(ele == None for ele in sub), test_list))
  
# printing result 
print("Removed None Tuples : " + str(res))

输出：

The original list is : [(None, 2), (None, None), (3, 4), (12, 3), (None,)]
Removed None Tuples : [(None, 2), (3, 4), (12, 3)]