Python - 将日期范围划分为 N 个相等的持续时间
给定两个日期，任务是将其划分为相等的持续时间，并获得每个划分点的确切时间。
Input : test_date1 = datetime.datetime(1997, 1, 4), test_date2 = datetime.datetime(1997, 1, 30) N = 7
Output : [datetime.datetime(1997, 1, 4, 0, 0), datetime.datetime(1997, 1, 7, 17, 8, 34, 285714), datetime.datetime(1997, 1, 11, 10, 17, 8, 571428), datetime.datetime(1997, 1, 15, 3, 25, 42, 857142), datetime.datetime(1997, 1, 18, 20, 34, 17, 142856), datetime.datetime(1997, 1, 22, 13, 42, 51, 428570), datetime.datetime(1997, 1, 26, 6, 51, 25, 714284)]
Explanation : List of dates of size 7 are returned with each date having equal delta between them.
Input : test_date1 = datetime.datetime(1997, 1, 4), test_date2 = datetime.datetime(1997, 1, 30) N = 4
Output : [datetime.datetime(1997, 1, 4, 0, 0), datetime.datetime(1997, 1, 10, 12, 0), datetime.datetime(1997, 1, 17, 0, 0), datetime.datetime(1997, 1, 23, 12, 0)]
Explanation : List of dates of size 4 are returned with each date having equal delta between them.
方法#1：使用循环
在此，我们使用整个持续时间除以 N 来计算每个段的持续时间。在此之后，每个日期是使用循环中的段持续时间乘法构建的。
Python3
# Python3 code to demonstrate working of
# Convert date range to N equal durations
# Using loop
import datetime
# initializing dates
test_date1 = datetime.datetime(1997, 1, 4)
test_date2 = datetime.datetime(1997, 1, 30)
# printing original dates
print("The original date 1 is : " + str(test_date1))
print("The original date 2 is : " + str(test_date2))
# initializing N
N = 7
temp = []
# getting diff.
diff = ( test_date2 - test_date1) // N
for idx in range(0, N):
# computing new dates
temp.append((test_date1 + idx * diff))
# using strftime to convert to userfriendly
# format
res = []
for sub in temp:
res.append(sub.strftime("%Y/%m/%d %H:%M:%S"))
# printing result
print("N equal duration dates : " + str(res))Python3
# Python3 code to demonstrate working of
# Convert date range to N equal durations
# Using generator function
import datetime
def group_util(test_date1, test_date2, N):
diff = (test_date2 - test_date1 ) / N
for idx in range(N):
# using generator function to solve problem
# returns intermediate result
yield (test_date1 + diff * idx)
yield test_date2
# initializing dates
test_date1 = datetime.datetime(1997, 1, 4)
test_date2 = datetime.datetime(1997, 1, 30)
# printing original dates
print("The original date 1 is : " + str(test_date1))
print("The original date 2 is : " + str(test_date2))
# initializing N
N = 7
# calling generator expression
temp = list(group_util(test_date1, test_date2, N))
# using strftime to convert to userfriendly format
res = []
for sub in temp:
res.append(sub.strftime("%Y/%m/%d %H:%M:%S"))
# printing result
print("N equal duration dates : " + str(res))输出：
The original date 1 is : 1997-01-04 00:00:00
The original date 2 is : 1997-01-30 00:00:00
N equal duration dates : [‘1997/01/04 00:00:00’, ‘1997/01/07 17:08:34’, ‘1997/01/11 10:17:08’, ‘1997/01/15 03:25:42’, ‘1997/01/18 20:34:17’, ‘1997/01/22 13:42:51’, ‘1997/01/26 06:51:25’]
方法#2：使用生成器函数
在这种情况下，我们使用生成器函数而不是循环方法执行产生中间结果的任务。唯一的区别是返回中间结果。
蟒蛇3
# Python3 code to demonstrate working of
# Convert date range to N equal durations
# Using generator function
import datetime
def group_util(test_date1, test_date2, N):
diff = (test_date2 - test_date1 ) / N
for idx in range(N):
# using generator function to solve problem
# returns intermediate result
yield (test_date1 + diff * idx)
yield test_date2
# initializing dates
test_date1 = datetime.datetime(1997, 1, 4)
test_date2 = datetime.datetime(1997, 1, 30)
# printing original dates
print("The original date 1 is : " + str(test_date1))
print("The original date 2 is : " + str(test_date2))
# initializing N
N = 7
# calling generator expression
temp = list(group_util(test_date1, test_date2, N))
# using strftime to convert to userfriendly format
res = []
for sub in temp:
res.append(sub.strftime("%Y/%m/%d %H:%M:%S"))
# printing result
print("N equal duration dates : " + str(res))
输出：
The original date 1 is : 1997-01-04 00:00:00
The original date 2 is : 1997-01-30 00:00:00
N equal duration dates : [‘1997/01/04 00:00:00’, ‘1997/01/07 17:08:34’, ‘1997/01/11 10:17:08’, ‘1997/01/15 03:25:42’, ‘1997/01/18 20:34:17’, ‘1997/01/22 13:42:51’, ‘1997/01/26 06:51:25’, ‘1997/01/30 00:00:00’]