提取网格匹配字符串的Python程序

给定一个包含缺失字符的字符网格，匹配与网格匹配的字符串。

例子：

Input : test_list = [“geeks”, “best”, “peeks”], mesh = “_ee_s” 
Output : [‘geeks’, ‘peeks’] 
Explanation : Elements according to mesh are geeks and peeks.

Input : test_list = [“geeks”, “best”, “test”], mesh = “_e_t” 
Output : [‘best’, ‘test’] 
Explanation : Elements according to mesh are best and test. 
 

方法#1：使用loop + all() + len() + zip()

以上的组合可以用来解决这个问题。在此，我们使用 zip() 和 all() 执行匹配网格和每个字符串的任务，用于检查所有字符串，使用 len() 测试匹配网格的字符串长度是否正确。

Python3

# Python3 code to demonstrate working of 
# Extract Mesh matching Strings
# Using len() + loop + zip() + all()
  
# initializing list
test_list = ["geeks", "best", "peeks", "for", "seeks"]
  
# printing original list
print("The original list : " + str(test_list))
  
# initializing mesh 
mesh = "_ee_s"
  
res = []
for sub in test_list:
      
    # testing for matching mesh, checking each character and length
    if (len(sub) == len(mesh)) and all((ele1 == "_") or (ele1 == ele2)
       for ele1, ele2 in zip(mesh, sub)):
        res.append(sub)
  
# printing result 
print("The extracted strings : " + str(res))

输出

The original list : ['geeks', 'best', 'peeks', 'for', 'seeks']
The extracted strings : ['geeks', 'peeks', 'seeks']

方法#2：使用列表理解

这以与上述方法类似的方式解决了该问题，唯一的区别是提供了 1 个 liner 解决方案。

蟒蛇3

# Python3 code to demonstrate working of 
# Extract Mesh matching Strings
# Using list comprehension
  
# initializing list
test_list = ["geeks", "best", "peeks", "for", "seeks"]
  
# printing original list
print("The original list : " + str(test_list))
  
# initializing mesh 
mesh = "_ee_s"
  
# one liner to solve this problem
res = [sub for sub in test_list if (len(sub) == len(mesh)) and all((ele1 == "_") or (ele1 == ele2)
      for ele1, ele2 in zip(mesh, sub))]
  
# printing result 
print("The extracted strings : " + str(res))

输出

The original list : ['geeks', 'best', 'peeks', 'for', 'seeks']
The extracted strings : ['geeks', 'peeks', 'seeks']