Python – 提取具有 Range 元素的元组

给定元组列表，提取具有范围内元素的元组。

Input : test_list = [(4, 5, 7), (5, 6), (3, 8, 10 ), (4, 10)], strt, end = 5, 6
Output : [(5, 6)]
Explanation : Only 1 tuple lies in range of 5-6.

Input : test_list = [(4, 5, 7), (5, 6), (3, 8, 10 ), (4, 10)], strt, end = 1, 10
Output : [(4, 5, 7), (5, 6), (3, 8, 10 ), (4, 10)]
Explanation : All lie in specified range.

方法 #1：使用列表理解 + all()

在此，我们使用运算符检查范围内的所有元素，并且 all() 对于包含指定范围内的元组的元组返回 true。

Python3

# Python3 code to demonstrate working of 
# Extract tuples with elements in Range
# Using all() + list comprehension
  
# initializing list
test_list = [(4, 5, 7), (5, 6), (3, 8, 10 ), (4, 10)]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing range 
strt, end = 4, 7
  
# list comprehension to encapsulate in 1 liner 
# all() checks for all elements in range 
res = [sub for sub in test_list if all(ele >= strt and ele <= end for ele in sub)]
          
# printing results
print("Filtered tuples : " + str(res))

输出

The original list is : [(4, 5, 7), (5, 6), (3, 8, 10), (4, 10)]
Filtered tuples : [(4, 5, 7), (5, 6)]

方法 #2：使用 filter() + lambda + all()

在此，我们使用 filter() 根据 lambda 提供的函数提取元组，并使用 all() 作为工具来测试范围元组中的所有元素。

Python3

# Python3 code to demonstrate working of 
# Extract tuples with elements in Range
# Using filter() + lambda + all() 
  
# initializing list
test_list = [(4, 5, 7), (5, 6), (3, 8, 10 ), (4, 10)]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing range 
strt, end = 4, 7
  
# list() to get back result as list  
# all() checks for all elements in range 
res = list(filter(lambda sub : all(ele >= strt and ele <= end for ele in sub), test_list))
          
# printing results
print("Filtered tuples : " + str(res))

输出

The original list is : [(4, 5, 7), (5, 6), (3, 8, 10), (4, 10)]
Filtered tuples : [(4, 5, 7), (5, 6)]