查找是否可以休假

给出以下值：

• N是剩余的考试天数。
• S是要准备考试的科目数。
• C是为每个主题准备的章节数。
• H是准备一章的小时数。
• L是所需假期的天数。在这个假期期间，无法完成学习。
• T是一天中可以学习的小时数。

任务是查找是否可以进行所需的假期。如果可以获取，则打印“是” ，否则打印“否” 。

例子：

Input: N = 1, S = 2, C = 3, H = 4, L = 5, T = 6
Output: No
required number of hours of study = S * C * H = 24
hours of study that can be done if the vacation is taken = (N – L) * T = -24
Since available time after vacation < total time required,
Hence vacation cannot be taken.

Input: N = 12, S = 5, C = 8, H = 3, L = 2, T = 20
Output: Yes
required number of hours of study = S * C * H = 120
hours of study that can be done if the vacation is taken = (N – L) * T = 200
Since available time after vacation > total time required,
Hence vacation can be taken.

方法：

1. 通过乘以S ， C和H来找到所需的学习小时数。

   required number of hours of study = S * C * H

2. 现在找到如果休假可以完成的学习时间。这些小时数等于我们剩下的剩余天数乘以T小时数(即(NL)* T)。

   hours of study that can be done if the vacation is taken = (N – L) * T

3. 现在检查所需时间是否少于或等于休假时可以完成的学习时间。如果为true，则打印“是” ，否则打印“否” 。

   下面是上述方法的实现：

   C++

   // C++ program to find
   // if the Vacation can be taken or not
     
   #include 
   using namespace std;
     
   // Function to find if the Vacation
   // is possible or not
   int isPossible(int N, int S, int C, int H,
                  int L, int T)
   {
     
       // Find the required number of hours of study
       int total_time_required = S * C * H;
     
       // find the hours of study that can be done
       // if the vacation is taken
       int available_time_after_vacation = (N - L) * T;
     
       // check if the required hours are less than
       // or equal to the hours of study
       // that can be done if the vacation is taken
       if (available_time_after_vacation
           >= total_time_required)
           return 1;
       return 0;
   }
     
   // Driver Code
   int main()
   {
       int N = 12, S = 5, C = 8,
           H = 3, L = 2, T = 20;
     
       if (isPossible(N, S, C, H, L, T))
           cout << "Yes" << endl;
       else
           cout << "No" << endl;
     
       N = 1, S = 2, C = 3,
       H = 4, L = 5, T = 6;
     
       if (isPossible(N, S, C, H, L, T))
           cout << "Yes" << endl;
       else
           cout << "No" << endl;
     
       return 0;
   }

   Java

   // Java program to find
   // if the Vacation can be taken or not
   class GFG
   {
     
   // Function to find if the Vacation
   // is possible or not
   static int isPossible(int N, int S, int C, int H,
                          int L, int T)
   {
     
       // Find the required number of hours of study
       int total_time_required = S * C * H;
     
       // find the hours of study that can be done
       // if the vacation is taken
       int available_time_after_vacation = (N - L) * T;
     
       // check if the required hours are less than
       // or equal to the hours of study
       // that can be done if the vacation is taken
       if (available_time_after_vacation
           >= total_time_required)
           return 1;
       return 0;
   }
     
   // Driver Code
   public static void main(String[] args)
   {
       int N = 12, S = 5, C = 8,
           H = 3, L = 2, T = 20;
     
       if (isPossible(N, S, C, H, L, T) == 1)
           System.out.print("Yes" + "\n");
       else
           System.out.print("No" + "\n");
     
       N = 1; S = 2; C = 3;
       H = 4; L = 5; T = 6;
     
       if (isPossible(N, S, C, H, L, T)==1)
           System.out.print("Yes" + "\n");
       else
           System.out.print("No" + "\n");
   }
   }
     
   // This code is contributed by 29AjayKumar

   Python3

   # Python3 program to find
   # if the Vacation can be taken or not
     
   # Function to find if the Vacation
   # is possible or not
   def isPossible(N, S, C, H, L, T):
         
       # Find the required number of hours of study
       total_time_required = S * C * H
         
       # find the hours of study that can be done
       # if the vacation is taken
       available_time_after_vacation = (N - L) * T
         
       # check if the required hours are less than
       # or equal to the hours of study
       # that can be done if the vacation is taken
       if (available_time_after_vacation >= total_time_required):
           return 1
       return 0
     
   # Driver Code
   N = 12
   S = 5
   C = 8
   H = 3
   L = 2
   T = 20
     
   if (isPossible(N, S, C, H, L, T)):
       print("Yes")
   else:
       print("No")
     
   N = 1
   S = 2
   C = 3
   H = 4
   L = 5
   T = 6
     
   if (isPossible(N, S, C, H, L, T)):
       print("Yes")
   else:
       print("No")
             
   # This code is contributed by SHUBHAMSINGH10

   C#

   // C# program to find
   // if the Vacation can be taken or not
   using System;
     
   class GFG
   {
     
   // Function to find if the Vacation
   // is possible or not
   static int isPossible(int N, int S, int C, int H,
                       int L, int T)
   {
     
       // Find the required number of hours of study
       int total_time_required = S * C * H;
     
       // find the hours of study that can be done
       // if the vacation is taken
       int available_time_after_vacation = (N - L) * T;
     
       // check if the required hours are less than
       // or equal to the hours of study
       // that can be done if the vacation is taken
       if (available_time_after_vacation
           >= total_time_required)
           return 1;
       return 0;
   }
     
   // Driver Code
   public static void Main(String[] args)
   {
       int N = 12, S = 5, C = 8,
           H = 3, L = 2, T = 20;
     
       if (isPossible(N, S, C, H, L, T) == 1)
           Console.Write("Yes" + "\n");
       else
           Console.Write("No" + "\n");
     
       N = 1; S = 2; C = 3;
       H = 4; L = 5; T = 6;
     
       if (isPossible(N, S, C, H, L, T)==1)
           Console.Write("Yes" + "\n");
       else
           Console.Write("No" + "\n");
   }
   }
     
   // This code is contributed by 29AjayKumar

   输出：

   Yes
   No