PyQt5 QDoubleSpinBox - 逐步

在本文中，我们将了解如何以编程方式逐步确定 QDoubleSpinBox 的值。双旋转框可以接受十进制值作为输入，我们可以借助setValue方法设置值，逐步将确定的数字加到当前值上，可以是正数也可以是负数。

注意：如果选择自适应类型，它将添加小数部分的值，否则将添加实部。

In order to do this we will use stepBy method with the double spin box object.
Syntax : dd_spin.stepBy(n)
Argument : It takes integer as argument
Return : It returns None

编程需要懂一点英语

下面是实现

Python3

# importing libraries
from PyQt5.QtWidgets import *
from PyQt5 import QtCore, QtGui
from PyQt5.QtGui import *
from PyQt5.QtCore import *
import sys
 
 
class Window(QMainWindow):
 
    def __init__(self):
        super().__init__()
 
        # setting title
        self.setWindowTitle("Python ")
 
        # setting geometry
        self.setGeometry(100, 100, 500, 400)
 
        # calling method
        self.UiComponents()
 
        # showing all the widgets
        self.show()
 
    # method for components
    def UiComponents(self):
 
        # creating double spin box
        d_spin = QDoubleSpinBox(self)
 
        # setting geometry to the double spin box
        d_spin.setGeometry(100, 100, 150, 40)
 
 
        # step type
        step_type = QAbstractSpinBox.AdaptiveDecimalStepType
 
        # adaptive step type
        d_spin.setStepType(step_type)
 
        # creating a label
        label = QLabel("GeeksforGeeks", self)
 
        # setting geometry to the label
        label.setGeometry(100, 200, 300, 80)
 
        # making label multi line
        label.setWordWrap(True)
 
        # push button
        push = QPushButton("Press", self)
 
        # setting geometry to the push button
        push.setGeometry(100, 150, 100, 35)
 
        # adding action to the push button
        # stepping by the value by 5
        push.clicked.connect(lambda: d_spin.stepBy(5))
 
 
 
 
# create pyqt5 app
App = QApplication(sys.argv)
 
# create the instance of our Window
window = Window()
 
# start the app
sys.exit(App.exec())

输出：