Python – 元组中的元素频率

给定一个元组，找出每个元素的频率。

Input : test_tup = (4, 5, 4, 5, 6, 6, 5) 
Output : {4: 2, 5: 3, 6: 2} 
Explanation : Frequency of 4 is 2 and so on..
Input : test_tup = (4, 5, 4, 5, 6, 6, 6) 
Output : {4: 2, 5: 2, 6: 3} 
Explanation : Frequency of 4 is 2 and so on.. 
 

方法 #1 使用 defaultdict()

在此，我们使用 defaultdict 执行获取所有元素并分配频率的任务，defaultdict 将每个元素映射到键，然后可以增加频率。

Python3

# Python3 code to demonstrate working of
# Elements frequency in Tuple
# Using defaultdict()
from collections import defaultdict
 
# initializing tuple
test_tup = (4, 5, 4, 5, 6, 6, 5, 5, 4)
 
# printing original tuple
print("The original tuple is : " + str(test_tup))
 
res = defaultdict(int)
for ele in test_tup:
     
    # incrementing frequency
    res[ele] += 1
 
# printing result
print("Tuple elements frequency is : " + str(dict(res)))

输出

The original tuple is : (4, 5, 4, 5, 6, 6, 5, 5, 4)
Tuple elements frequency is : {4: 3, 5: 4, 6: 2}

方法 #2：使用 Counter()

这是解决此问题的直接方法。在这种情况下，我们只使用此函数，它返回容器中元素的频率，在本例中为元组。

Python3

# Python3 code to demonstrate working of
# Elements frequency in Tuple
# Using Counter()
from collections import Counter
 
# initializing tuple
test_tup = (4, 5, 4, 5, 6, 6, 5, 5, 4)
 
# printing original tuple
print("The original tuple is : " + str(test_tup))
 
# converting result back from defaultdict to dict
res = dict(Counter(test_tup))
 
# printing result
print("Tuple elements frequency is : " + str(res))

输出

The original tuple is : (4, 5, 4, 5, 6, 6, 5, 5, 4)
Tuple elements frequency is : {4: 3, 5: 4, 6: 2}