检查是否可以创建具有给定角度的多边形

给定一个角度$a$在哪里， $1\le a< 180$ .任务是检查是否可以制作一个所有内角都等于的正多边形$a$ .如果可能，则打印“YES”，否则打印“NO”（不带引号）。
例子：

Input: angle = 90
Output: YES
Polygons with sides 4 is
possible with angle 90 degrees.

Input: angle = 30
Output: NO

方法：内角定义为正多边形任意两条相邻边之间的夹角。
它是由$\;Interior\;angle = \frac{180 \times (n-2)}{n}\;$其中， n是多边形的边数。
这可以写成$\;a = \frac{180 \times (n-2)}{n}\;$ .
在重新排列的条件下，我们得到， $\;n = \frac{360}{180 - a}\;$ .
因此，如果n是整数，则答案为“是”，否则，答案为“否”。
下面是上述方法的实现：

C++

// C++ implementation of above approach
#include 
using namespace std;
 
// Function to check whether it is possible
// to make a regular polygon with a given angle.
void makePolygon(float a)
{
    // N denotes the number of sides
    // of polygons possible
    float n = 360 / (180 - a);
    if (n == (int)n)
        cout << "YES";
    else
        cout << "NO";
}
 
// Driver code
int main()
{
    float a = 90;
 
    // function to print the required answer
    makePolygon(a);
 
    return 0;
}

Java

class GFG
{
// Function to check whether
// it is possible to make a
// regular polygon with a given angle.
static void makePolygon(double a)
{
    // N denotes the number of
    // sides of polygons possible
    double n = 360 / (180 - a);
    if (n == (int)n)
        System.out.println("YES");
    else
        System.out.println("NO");
}
 
// Driver code
public static void main (String[] args)
{
    double a = 90;
 
    // function to print
    // the required answer
    makePolygon(a);
}
}
 
// This code is contributed by Bilal

Python3

# Python 3 implementation
# of above approach
 
# Function to check whether
# it is possible to make a
# regular polygon with a
# given angle.
def makePolygon(a) :
 
    # N denotes the number of sides
    # of polygons possible
    n = 360 / (180 - a)
 
    if n == int(n) :
        print("YES")
 
    else :
        print("NO")
 
# Driver Code
if __name__ == "__main__" :
    a = 90
 
    # function calling
    makePolygon(a)
     
# This code is contributed
# by ANKITRAI1

C#

// C# implementation of
// above approach
using System;
 
class GFG
{
// Function to check whether
// it is possible to make a
// regular polygon with a
// given angle.
static void makePolygon(double a)
{
    // N denotes the number of
    // sides of polygons possible
    double n = 360 / (180 - a);
    if (n == (int)n)
        Console.WriteLine("YES");
    else
        Console.WriteLine("NO");
}
 
// Driver code
static void Main()
{
    double a = 90;
 
    // function to print
    // the required answer
    makePolygon(a);
}
}
 
// This code is contributed by mits

Javascript

 
      // JavaScript implementation of above approach
      // Function to check whether it is possible
      // to make a regular polygon with a given angle.
       
      function makePolygon(a)
      {
        // N denotes the number of sides
        // of polygons possible
        var n = parseFloat(360 / (180 - a));
        if (n === parseInt(n))
        document.write("YES");
        else
        document.write("NO");
      }
 
      // Driver code
      var a = 90;
       
      // function to print the required answer
      makePolygon(a);
       

输出：

YES