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📜  C++ STL-math.lrint()函数

📅  最后修改于: 2020-10-18 13:27:16             🧑  作者: Mango

C++ STL math.lrint()

该函数使用当前舍入模式舍入给定值，并返回long int类型的值。

句法

假设数字是“ x”。语法为：

long int lrint(data_type x);

参数

x：可以是float，double或long double的值。

返回值

它返回x的舍入值，并且该值的返回类型为long int。

例子1

让我们看一个简单的例子。

#include 
#include
#include 
using namespace std;
int main()
{
    float r;
    int str;
    cout<<"Enter the value which you want to round :";
    std::cin >> r ;
    cout<<'\n';
    cout<<"Name of the methods are :"<<'\n'<<"1. Rounding downwards"<<'\n'<<"2. Rounding upwards"<<'\n'<<"3. 
    Rounding towards zero"<<'\n'<<"4. Rounding to the nearest"<<'\n';
    cout<<"Enter the number of rounding method :";
    cin>>str;
    cout<<'\n';
    switch(str)
    {
        case 1:
        fesetround(FE_DOWNWARD);
        cout<<"Rounding downwards,value is :"<

输出：

Enter the value which you want to round : 7.8

Name of the methods are :
1. Rounding downwards
2. Rounding upwards
3. Rounding towards zero
4. Rounding to the nearest
Enter the number of rounding method : 1

Rounding downwards,value is :7